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LekaFEV [45]
3 years ago
14

barry has 1/3 of bag a candy left over from his party .of this candy ,1/3 of it is chocolate .how much of the total bag is choco

late?
Mathematics
1 answer:
DiKsa [7]3 years ago
6 0

Answer:

1/6

Step-by-step explanation:

if there is 1/3 bag of candy, 1/3 of 1/3 is 1/9

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<h2>Answer:</h2>

The probability that exactly one customer dines on the first floor is:

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<h2>Step-by-step explanation:</h2>

We need to use the binomial theorem to find the probability.

The probability of k success in n experiments is given by:

       P(X=k)=n_C_k\cdot p^k\cdot (1-p)^{n-k}

where p is the probability of success.

Here p=1/3

( It represents the probability of choosing first floor)

k=1 ( since only one customer has to chose first floor)

n=6 since there are a total of 6 customers.

This means that:

P(X=1)=6_C_1\times (\dfrac{1}{3})^1\times (1-\dfrac{1}{3})^{6-1}\\\\\\P(X=1)=6\times (\dfrac{1}{3})\times (\dfrac{2}{3})^5\\\\\\P(X=1)=0.26337

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