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lesya [120]
3 years ago
7

Find the correct value for x in the point (x, 15), which is a point on the line in the graph below

Mathematics
1 answer:
slega [8]3 years ago
4 0
The answer would be x = 16
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Please help the question is in the picture.
jeyben [28]

Because thee dimensions of ΔRAH is twice as large as corresponding dimensions of ΔEAC,

|RA|=2|EA|=2*3.5=7

|AH|=2|AC|=2*6=12

So, we have that 2 corresponding sides are in proportion and angle between them =90⁰, so the angle between them are congruent,

we can use SAS to prove that these triangles are similar.

4 0
4 years ago
Each day at school Kai records his homework assignments in a small notebook each page of the notebook measures 2 1/4 inches by 3
telo118 [61]
7 7/8 inches

All I did was multiply 2 1/4 by 3 1/2.

I hope this helps!
4 0
3 years ago
Elena is designing a paint can with thickness ttt millimeters and height hhh centimeters. She calculates that the thickness of t
Degger [83]

Answer:

t \ge h and t + 0.5h \le 12.0

Step-by-step explanation:

Given

t= thickness

h =height

From the first statement, we have that:

t\ mm \ge 0.1 * h\ cm

Convert mm to cm

t\ * 0.1*cm \ge 0.1 * h\ cm

t\ *0.1 \ge 0.1 * h

Divide both sides by 0.1

t \ge h

From the second statement, we have that:

Cost \le 12.2

Substitute 0.2 + t + 0.5h for Cost

0.2 + t + 0.5h \le 12.2

Collect Like Terms:

t + 0.5h \le 12.2-0.2

t + 0.5h \le 12.0

So, the inequalities are:

t \ge h and t + 0.5h \le 12.0

8 0
3 years ago
A landscaping company charges customers for lawn care based on the area of their yards. Mr. Jones was charged $52 for his yard,
crimeas [40]

Answer:

Landscaping Company will charge $80 for Neighbor yard.

Step-by-step explanation:

Given:

Charges of Mr. Jones = $52

Length of Mr. Jones yard = 65 feet

Width of Mr. Jones yard = 40 feet

Now we will find the area of Mr. Jones yard.

Yard is basically in rectangular form.

Hence we can;

Area of yard is equal to product of length of the yard and width of the yard.

Framing in equation we get;

Area of Mr. Jones Yard = 40\times 65 = 2600\ ft^2

Now Mr. Jones was charged $52 for a yard having Area 2600 sq. ft.

So we will find the per sq. ft charge applied by the company.

Per sq. ft charge will be equal to Charges of Mr. Jones divided by Area of Mr. Jones Yard.

Framing in equation form we get;

Per sq. ft charge = \frac{52}{2600} = \$0.02

Hence the Landscaping company charge Mr. Jones at $0.02 per sq.ft.

Now Given:

Length of Neighbor yard = 80 ft.

Width of Neighbor yard = 50 ft.

We need to find the Charges on Neighbor based on charges applied on Mr. Jones.

First we will find the Area of Neighbors yard we get;

Area of Neighbors yard = 80 \times50 = 4000\ ft^2

Charges of Neighbor yard will be equal to charges Landscaping company for per sq. ft multiplied by area of Neighbors yard.

Framing in equation form we get;

Charges of Neighbor yard = 0.02\times 4000 = \$80

Hence Landscaping Company will charge $80 for Neighbor yard.

8 0
3 years ago
Which of the following is a polynomial?
elena-14-01-66 [18.8K]
…………………………. I think it’s B
5 0
3 years ago
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