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Kruka [31]
3 years ago
13

Find the area of the triangle

Mathematics
1 answer:
BARSIC [14]3 years ago
3 0

Answer:

The Area of Δ ABC = 219.13

Step-by-step explanation:

<em>The hard part about this problem is finding the area without the height</em>

The formula to do this is Area = \sqrt{S(S-A)(S-B)(S-C)}

A, B, C represent the sides

S represents \frac{1}{2} (A + B + C)

In this equation, we will make the base be A, and the other two sides will be B and C

<u>Sides B and C are the same length</u> because they meet at a 90° angle

Lets plug the numbers into the variables

A = 28

B= 21

C= 21

<u>Remember:</u> S represents  \frac{1}{2}  (A + B + C)

S =  \frac{1}{2} (28 + 21 + 21)

S =  \frac{1}{2} (70)

S = 35

<em>Lets plug the numbers into the Area Formula now!</em>

Area = \sqrt{35(35 - 28)(35 - 21)(35 - 21)}

According to the order of operations, we need to do the calculations in parentheses <u>first</u>

35 - 28 = 7

35 - 21 = 14

35 - 21 = 14

14 x 14 x 7 = 1372

1372 x 35 = 48020

\sqrt{48020} = 219.13

The Area of Δ ABC = 219.13

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