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marshall27 [118]
3 years ago
9

2x+8y=3 and 4x-3y=2 value of x and y.. plzz help me​

Mathematics
1 answer:
lesya692 [45]3 years ago
6 0

Answer:  

<u>Set a system of equations:</u>

\left \{ {{2x+8y=3} \atop {4x-3y=2}} \right.

<u>Multiply the whole upper equation by 2 and the whole bottom equation by 1 so their x-value equals:</u>

\left \{ {{2(2)x+8(2)y=3(2)} \atop {4(1)x-3(1)y=2(1)}} \right.\\\\=\left \{ {{4x+16y=6} \atop {4x-3y=2}} \right.

<u>Subtract the upper equation by the bottom equation & solve for y:</u>

(4x-4x)+(16y-(-3y))=6-2\\\\19y=4\\\\y=\frac{4}{19}

<u>Substitute in the y-value to a equation to find x:</u>

2x+8y=3\\\\2x+8(\frac{4}{19} )=3\\\\2x=3-\frac{32}{19} =\frac{57}{19} -\frac{32}{19} =\frac{25}{19} \\\\x=\frac{\frac{25}{19}}{2} =\frac{25}{19}*\frac{1}{2} =\frac{25}{38}

<u>Therefore, the answer would be:</u>

<u />\left \{ {{y=\frac{4}{19} } \atop {x=\frac{25}{38} }} \right.

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