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3 years ago

PLEASE HELP AND GET POINTS!

Mathematics

2 answers:

bezimeni [28]3 years ago

5 0

Answer:

i think 6 x 72 = calculator

Step-by-step explanation:

MatroZZZ [7]3 years ago

3 0

Answer:

6 x 70 = calculator

Step-by-step explanation:

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GIVING 100 POINTS!!!!

IrinaK [193]

Answer:

As per dot plots we see the distribution of prices is close but majority of prices are concentrated in different zones. So MAD would be more similar by the look.

Let's verify

<h3>Neighborhood 1</h3>

Data

55, 55, 60, 60, 70, 80, 80, 80, 90, 120

Mean

(55*2+ 60*2+ 70+ 80*3 + 90+ 120)/10 = 75

MAD

(20*2+15*2+5+5*3+15+45)/10 = 15

<h3>Neighborhood 2</h3>

Data

100, 110, 110, 110, 120, 120, 120, 140, 150, 160

Mean

(100 + 110*3+ 120*3+ 140 + 150+ 160)/10 = 124

MAD

(24+14*3+4*3+16*3+16+26+36)/10 = 20.4

As we see the means are too different (75 vs 124) than MADs (15 vs 20.4).

7 0

3 years ago

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I need this fast guys. This is due tomorrow help a fellow comrade out

gavmur [86]

So whats the answer. please help me I got a test of this

3 0

3 years ago

Ray LN is the perpendicular bisector of segment JK.

scoray [572]

Answer:

ok i think "kp" is 17x but i am not 100% sure

Step-by-step explanation:

3 0

3 years ago

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Is : -.6 IRRATIONAL? yes or no

Anastaziya [24]

Answer:

I would say -6 is an irrational number.

Step-by-step explanation:

Either way, -6 is a rational number, because it can be expressed as a fraction where the numerator and denominator are integers and the denominator doesn't equal 0.

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My question box doesn´t work.

7 0

3 years ago

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Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 a

krok68 [10]

Answer:

Jessie scored higher than Reagan.

Step-by-step explanation:

We are given that Reagan scored 1140 on the SAT. The distribution of SAT scores in a reference population is normally distributed with mean 1000 and standard deviation 100.

Jessie scored 30 on the ACT. The distribution of ACT scores in a reference population is normally distributed with mean 17 and standard deviation 5.

For finding who performed better on the standardized exams, we have to calculate the z-scores for both people.

1. Finding z-score for Reagan;

Let X = distribution of SAT scores

SO, X ~ Normal( $\mu=1000, \sigma^{2}=100^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 1000

$\sigma$ = standard deviation = 100

Now, Reagan scored 1140 on the SAT, that is;

z-score = $\frac{1140-1000}{100}$ = 1.4

2. Finding z-score for Jessie;

Let X = distribution of ACT scores

SO, X ~ Normal( $\mu=17, \sigma^{2}=5^{2}$ )

The z-score probability distribution for the normal distribution is given by;

Z = $\frac{X-\mu}{\sigma}$ ~ N(0,1)

where, $\mu$ = population mean = 17

$\sigma$ = standard deviation = 5

Now, Jessie scored 30 on the ACT, that is;

z-score = $\frac{30-17}{5}$ = 2.6

This means that Jessie scored higher than Reagan because Jessie's standardized score was 2.6, which is 2.6 standard deviations above the mean and Reagan's standardized score was 1.4, which is 1.4 standard deviations above the mean.

6 0

3 years ago