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Novay_Z [31]
3 years ago
5

Find the product of quotient using only positive exponents

Mathematics
1 answer:
emmasim [6.3K]3 years ago
6 0

Answer:

ok wait wait innedd fmto figure

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I don't know how to do this or what i'm doing plz help
mote1985 [20]

recalling that d = rt, distance = rate * time.


we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?


\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}


so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.


\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}


\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}

7 0
3 years ago
What is 28 over 35 reduced to
USPshnik [31]
We can simplify by 7

28/7 = 4
35/7 = 5

Answer- 4/5
8 0
3 years ago
Read 2 more answers
The height h in feet of a ball thrown vertically upward from the top of a 288-foot tall building is given by h=288+48t-16t^2 whe
mr Goodwill [35]

6 sec can take penny to strike the ground.

Solution:

Given data:

H_0=288 feet

V_0=48 feet

h(t)=288+48t-16t^2

Re-arrange the terms from greatest degree to smallest degree.

h(t)=-16t^2+48t+288

We can solve it by applying quadratic formula,

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Here a = –16, b = 48, c = 288

$t=\frac{-48\pm \sqrt{48^2-4(-16)(288)}}{2(-16)}

$t=\frac{-48\pm \sqrt{2304+18432}}{-32}

$t=\frac{-48\pm \sqrt{20736}}{-32}

$t=\frac{-48\pm144}{-32}

Now, write find two t's using plus and minus operation.

$t=\frac{-48+144}{-32},\ \ t=\frac{-48-144}{-32}

$t=\frac{96}{-32},\ \ t=\frac{-192}{-32}

t = –3 (or)   t = 6

We cannot write time is negative. so neglect t = –3.

Therefore t = 6.

Hence 6 sec can take penny to strike the ground.

8 0
3 years ago
Simplify. t^-6 * t^2
Deffense [45]
<span>t^-6 * t^2
= t^-4

hope it helps</span>
8 0
3 years ago
Help me pls , will give brainliest
shusha [124]

Answer:

m/2 = 87°

m/4 = 87°

m/7 = 93°

Have a good day, please! :)

5 0
2 years ago
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