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2 years ago

Question Two please help

Mathematics

1 answer:

lana66690 [7]2 years ago

8 0

Answer:

The similarity statement is RTS and ACB. Other options are correct

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What number could replace kkk below? \dfrac{k}{100} = \dfrac{1}{10} 100 k = 10 1 start fraction, k, divided by, 100, end fra

Ivanshal [37]

Answer:

Step-by-step explanation:

Given the equation;

$\dfrac{k}{100} = \dfrac{1}{10}$

We are to find the value of k.

Cross multiply;

$\dfrac{k}{100} = \dfrac{1}{10} \\10 \times k = 100 \times 1\\10k = 100\\$

Divide both sides by 10

$10k/10 = 100/10\\k = 10$

Hence the value of k is 10

6 0

2 years ago

Lim x-1 x2 - 1/ sin(x-2)

balu736 [363]

Answer:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=0$

Explanation:

Assuming the correct expression is to find the following limit:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}$

Use the property the limit of the quotient is the quotient of the limits:

$\lim_{x \to 1}\frac{x^2-1}{sin(x-2)}=\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}$

Evaluate the numerator:

$\frac{\lim_{x \to 1}x^2-1}{\lim_{x \to 1}sin(x-2)}=\frac{1^2-1}{\lim_{x \to1}sin(x-2)}=\frac{0}{\lim_{x \to 1}sin(x-2}$

Evaluate the denominator:

Since $\lim_{x \to1}sin(x-2)\neq 0$

$\frac{0}{\lim_{x \to1}sin(x-2)}=0$

4 0

2 years ago

Clare is paid $90 for 5 hours of work. At thos rate how many seconds does i take for her to earn 25 cents?

natka813 [3]

We are given

Clare is paid $90 for 5 hours of work

Total money paid =$90

total hours of work =5 hours

so, firstly we will find rate of work

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

and we get

The rate of work is

$=\frac{90}{5}$

$=18$ $/ hour

now, we have to find time for amount paid is 25 cents

so, amount paid =25 cents

100 cents =1$

so, amount paid =$ 0.25

Since, the rate is constant

so, we can take same rate here

now, we can use formula

rate of work = ( total money paid)/( total hours of work)

now, we can plug values

$18=\frac{0.25}{T}$

now, we can solve for T

$T=\frac{0.25}{18}$ hour

since, T is in hours

so, we can change into seconds

1 hour =3600seconds

so, we can plug

$T=\frac{0.25}{18}\times 3600$ seconds

$T=50$ seconds......................Answer

6 0

2 years ago

Solve each equation. Record your work and check your solution. <br> a. 5(x-2)+(-9)= -7(1-x)

Daniel [21]

The solution for equation is x = -6

<em><u>Solution:</u></em>

<em><u>Given equation is:</u></em>

$5(x-2) + (-9) = -7(1-x)$

We have to solve the equation

According to Bodmas rule, if an expression contains brackets ((), {}, []) we have to first solve or simplify the bracket followed by of (powers and roots etc.), then division, multiplication, addition and subtraction from left to right

Therefore, solve for brackets in given equation

$5(x-2) + (-9) = -7(1-x)\\\\5x - 10 -9 = -7 + 7x$

Solve for terms in left hand side of equation

$5x - 19 = -7+7x$

Move the variables to one side and constants to other side

$7x -5x = -19+7\\\\2x = -12\\\\Divide\ both\ sides\ by\ 2\\\\x = -6$

Thus the solution for equation is x = -6

8 0

2 years ago

8x6+(12-4)/2 equal what is sum???

algol13

$8 \times 6 + \dfrac{(12-4)}{2}$

$=48+ \dfrac{8}{2}$

$=48 + 4$

$=52$

8 0

3 years ago

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