The pool has area
.
Let
be the width of the sidewalk. Then the combined area of the pool and sidewalk is
, so that the area of the sidewalk alone is
.
We're told this area is
, so

Answer:
( 0 < y < 23 / 6 ) mins
Step-by-step explanation:
Solution:-
We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.
The time taken to give her speech must always be less than 4 minutes. We can express this mathematically using an inequality as follows:
( 0 < x < 4 ) minutes
Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

The time taken by Jo Anne to complete her speech in English class can be represented as:
y = x - 1/6
Using the range of time that Jo Anne could take in delivering her speech in the class would be:
0 < x < 4
0 - 1/6 < y < 4 - 1/6
-1/6 < y < 23 / 6
Since time can not be less than zero. We correct the lower limit to " 0 " as follows:
( 0 < y < 23 / 6 ) mins
Let the first number of the five we are looking for equal n.
Because the numbers are consecutive, the next four can be expressed as (n+1), (n+2), (n+3) and (n+4).
Our series of 5 numbers is therefore n,(n+1),(n+2),(n+3),(n+4).
We are told the sum of the squares of the first 3 is equal to the sum of the squares of the last 2 therefore:
n² + (n+1)² + (n+2)² = (n+3)² + (n+4)²
expand all the brackets to give
n² + n² + 2n + 1 + n² + 4n + 4 = n² + 6n + 9 + n² + 8n + 16
3n²+6n+5 = 2n²+14n+25
n²-8n-20=0
factorising this gives us
(n+2)(n-10) = 0 so the solutions are n=10 and n=-2
That means that n,(n+1),(n+2),(n+3),(n+4) could be [-2, -1, 0, 1 and 2] or [10, 11, 12, 13 and 14].
Since the question asks for whole numbers, and negative numbers are not classed as whole numbers, the numbers we want must be 10, 11, 12, 13 and 14.
You can check this on a calculator by doing 10² + 11² + 12² (=365) and 13² + 14² (=365).
Answer:
You can cut the grass for 2 1/2 hours.
Step-by-step explanation:
Length=2w+59
the perimeter would be:
2w+2(2w+59)
2w+4w+118
P=6w+118