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8090 [49]
4 years ago
9

30 points !!! Polygon ABCDE is reflected to produce polygon A?B?C?D?E?. What is the equation for the line of reflection? a. Y =

0 b. X = 0 c. X = 2 d. Y = 1
Mathematics
2 answers:
Gnoma [55]4 years ago
7 0

Answer:0

Step-by-step explanation:

azamat4 years ago
4 0

Answer:

B. x=0

Step-by-step explanation:

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Negative time a negative equals a positive!

Step-by-step explanation:

When you multiply two negative numbers or two positive numbers then the product is always positive. The same also goes for dividing negative integers.

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A retirangle has an area of 40 units.the lenght is 6 units greater then the width
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40 units multiply by 6 units equal 240 units

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I don't understand how I'm suppose to find the height of point A above the ground...I don't get it.
olga_2 [115]
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5 0
4 years ago
А. 40 <br><br>ОВ. 5<br><br> Ос. 20<br><br> OD. 45 ​
Zina [86]

Answer:

A. 40

Step-by-step explanation:

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4 0
3 years ago
You must design a closed rectangular box of width w, length l and height h, whose volume is 504 cm3. The sides of the box cost 3
Charra [1.4K]

Answer:

Dimensions will be

Length = 7.23 cm

Width = 7.23 cm

Height = 9.64 cm

Step-by-step explanation:

A closed box has length = l cm

width of the box = w cm

height of the box = h cm

Volume of the rectangular box = lwh

504 = lwh

h=\frac{504}{lw}

Sides which involve length and width and height, cost = 3 cents per cm²

Top and bottom of the box costs = 4 cents per cm²

Cost of the sides C_{s}= 3[2(l + w)h] = 6(l + w)h

C_{s}= 3[2(l + w)h]

C_{s}=6(l+w)(\frac{504}{lw} )

Cost of the top and the bottom C_{(t,p)}= 4(2lw) = 8lw

Total cost of the box C = 3024\frac{(l+w)}{lw} + 8lw

                                      = 3024[\frac{1}{l}+\frac{1}{w}] + 8lw

To minimize the cost of the sides

\frac{dC}{dl}=3024(-l^{-2}+0)+8w=0

\frac{3024}{l^{2}}=8w

\frac{378}{l^{2}}=w ---------(1)

\frac{dC}{dw}=3024(-w^{-2})+8l=0

\frac{3024}{w^{2}}=8l

\frac{378}{w^{2}}=l

w^{2}=\frac{378}{l}-------(2)

Now place the value of w from equation (1) to equation (2)

(\frac{378}{l^{2}})^{2}=\frac{378}{l}

\frac{(378)^{2} }{l^{4}}=\frac{378}{l}

l³ = 378

l = ∛378 = 7.23 cm

From equation (2)

w^{2}=\frac{378}{7.23}

w^{2}=52.28

w = 7.23 cm

As lwh = 504 cm³

(7.23)²h = 504

h=\frac{504}{(7.23)^{2}}

h = 9.64 cm                        

6 0
4 years ago
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