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pychu [463]
3 years ago
12

Reputable firms often ask recent graduates to pay an up-front fee for a job.

Computers and Technology
2 answers:
dolphi86 [110]3 years ago
6 0

Answer:

hi your question is not complete it think the complete question you are asking is

"do reputable firms often ask for recent graduates to pay an up-front fee for a job true or false"

the answer is FALSE

Explanation:

Reputable firms are firms that are very much accountable to their customers, the good cause of the company and as well to their shareholders (stake holders)  reputable firms care a lot about their public image and more especially how they conduct their services including recruitment as well. based on this definition reputable firms does not ask recent graduates to pay an up-front fee for a job.

non-reputable firms are mostly fraudulent firms with little or no regard for stakeholders or the good cause of the company they don't as well care about their public image

koban [17]3 years ago
5 0

Answer:

What is your question?

Explanation:

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Yes, "technology" doesn't have to be all about computers or cell phones.. Technology is anything that is a new advance in knowledge and books were once a great advance in that field.
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4 years ago
Read 2 more answers
The game begins with the player having 20 POINTS
kompoz [17]

Answer:

Following are the code to this question:

import random#import package for using random method  

def rolling_dice(): #defining method rolling_dice that uses a random number to calculate and add value in dice1 and dice2 variable

   dice1 = random.randint(1,6)

   dice2 = random.randint(1,6)

   return dice1 + dice2

def rolling(): # defining method rolling

   n_roll = 0  # defining num variable that initial value that is 0.

   p = 20 # defining variable p for looping, that points in between 1 and 59

   while p > 0 and p < 60: # defining loop that counts value dice value two times  

       d = rolling_dice()#defining d variable that hold method value

       n_roll+= 1 #defining n_roll that increment n_roll value by 1

       if d == 7 or d == 11:# defining if block that uses the d variable that checks either 7 or 11, player won d in p variable

           p+= d   # use p variable that adds d variable

       elif d == 2 or d == 3 or d == 12:#defining elif block to that checks d variable by using or operator  

           p-= d#defining d variable that decreases d variable variable

       else: # defining else block

           p1 = d # using p1 variable that store d value  

           while True:# defining loop that calculates values

               d = rolling_dice()#defining d variable that holds method values

               n_roll += 1 #increment the n_roll value by 1

               if d == 7:#defining if block that checks d value equal to 7

                   p -= p1#subtract the value of p1 in p variable  

                   break # exit loop

               elif d == p:#defining elif block to check d value is equal to p

                   p += p1#adds the value of p1 in p variable  

                   break#using break keyword

   if p<= 0:#defining if block that checks p-value is less then equal to 0  

       print('Player lost')#using print method

   elif p>= 60:#defining else block that checks p-value is greater than equal to 60

       print('Player won')#using print method to print the value

   print('number of dice rolls:', n_roll)#use print method to print n_rolls value

rolling()

Output:

Player lost

number of dice rolls: 38

Explanation:

In the above-given python code, a method "rolling_dice" is declared, inside the method two-variable "dice1 and dice2" is declared, that uses the random method to calculate the value in both variable and use the return keyword to add both values.

  • In the next step, another method the "rolling"  is declared, inside the method "n_roll and p" is declared that assigns the values and use the two while loop, inside the loop if block is defined that calculates the values.
  • In the next step, a condition block is used that stores value in the p variable and use the print method to print the "n_roll" value.  
8 0
3 years ago
What command utilizes the limpel-ziv (lz77) compression algorithm and achieves a compression ratio of 60-70 percent?
AURORKA [14]

The limpel-ziv (lz77) compression technique is used by the GNU zip (gzip) tool to produce a compression ratio of 60–70%.

<h3>How do methods for data compression function? Describe the LZW algorithm.</h3>

Compression methods lower the amount of memory needed to hold pictures and the number of bytes needed to represent data. Compression improves the amount of data that can be delivered over the internet and enables the storage of more photos on a given media.

Abraham Lempel, Jacob Ziv, and Terry Welch developed the table-based lookup technique known as LZW compression to compress a file into a smaller file. The TIFF image format and the GIF image format are two frequently used file formats that employ LZW compression.

To know more about limpel-ziv (lz77) compression algorithm, Visit:

<u>brainly.com/question/19878993</u>

#SPJ4

4 0
1 year ago
How would I view the ruler on my document if it was not visible
svlad2 [7]
For MS Word 2010 and higher
Go to "View" and find checkbox "Ruler"
8 0
4 years ago
What is administrator access? Multiple Choice refers to how quickly a system can transform to support environmental changes perf
IrinaVladis [17]

Answer:

Administrator access is:

refers to the varying levels that define what a user can access, view, or perform when operating a system refers to the time frames when the system is operational

Explanation:

The reasons behind this answer are that in the first place the administrator role is the maximum role an account can have in the operating system. Controlling the different levels of access the rest of the accounts can have on the system. It then is a hierarchical role, not the changes someone can execute in a certain environment, these are called rules.

3 0
3 years ago
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