Answer:
6.4 units
Step-by-step explanation:
Distance² = (change in y)² + (change in x)²
Distance² = (4 - -1)² + (-8 - -4)²
Distance² = 25 + 16 = 41
Distance = 
= 6.403124237
The distance is 6.4 units (rounded off to nearest tenth)
Answer=$3.20
8%=0.08
$40.00*0.08=$3.20
The markup was $3.20
Answer:
The data that we have is:
"Adrian's backyard pool contains 6.4 gallons of water. Adrian will begin filling his pool at a rate of 4.1 gallons per second."
Then we can write the amount of water in Adrian's pool as a linear function:
A(t) = 6.4gal + (4.1gal/s)*t
Where t is our variable and represents time in seconds.
We also know that:
"Dale's backyard pool contains 66.4 gallons of water. Dale will begin draining his pool at a rate of 0.9 gallons per second. "
We can also model this with a linear function:
D(t) = 66.4 gal + (0.9gal/s)*t
Both pools will have the same amount of water when:
D(t) = A(t)
So we can find the value of t:
6.4gal + (4.1gal/s)*t = 66.4 gal + (0.9gal/s)*t
(4.1gal/s)*t - (0.9gal/s)*t = 66.4gal - 6.4gal
(3.2gal/s)*t = 60gal
t = 60gal/(3.2gal/s) = 18.75s
In 18.75 seconds both pools will have the same amount of water.
Answer:
Step-by-step explanation:
cos(∠X) = adj./hyp.
arccos(adj./hyp.) = ∠X
arccos(13/18) = 43.761...≈ 43°
