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4 years ago

Which expression represents "8 times the difference of 52 and 9"?

Mathematics

2 answers:

Mariulka [41]4 years ago

6 0

Answer:

8(52-9)=

8x41=

328

Step-by-step explanation:

andreyandreev [35.5K]4 years ago

4 0

Answer:

(52-9)*8

:):):):):):)

pls make me brainliest!!!

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there are 3 people who work full-time and are to work together on a project but their total time on the project is to be equival

mina [271]

The problem express that the fraction of time worked by the three people need to be equivalent to one person working full time. This means that the fraction need to add up to one. We know one person works ½ time on the project and another works one third 1/3 time.

Given:

A = the amount of time that the third person needs to work on the job to add up to one

1 = ½ +1/3 + A

1 – ½ - 1/3 = A

To subtract the fractions put them all over a common denominator. Use 3 * 2 as the denominator.

1=6/6, ½ = 3/6, 1/3 = 2/6

A = 6/6 – 3/6 – 2/6

A = 1/6 , The third person must work on the project

6 0

3 years ago

(1,9),m=4 in intercept from

kiruha [24]

Y = 4x + b
9 = 4(1) + b

7 0

3 years ago

You roll two fair dice, a green one and a red one. (a) What is the probability of getting a sum of 7? (Enter your answer as a fr

Lera25 [3.4K]

Answer:

a) 0.167 b)0.056 c)0.023

Step-by-step explanation:

We are given the following information:

Sample space = {(1,1),(1,2),(1,3),(1,4),(1,5),(1,6)

(2,1),(2,2),(2,3),(2,4),(2,5),(2,6)

(3,1),(3,2),(3,3),(3,4),(3,5),(3,6)

(4,1),(4,2),(4,3),(4,4),(4,5),(4,6)

(5,1),(5,2),(5,3),(5,4),(5,5),(5,6)

(6,1),(6,2),(6,3),(6,4),(6,5),(6,6)}

Total number of outcomes = 36

Formula:

$\text{Probability} = \displaystyle\frac{\text{Number of favourable outcomes}}{\text{Total number of outcomes}}$

a) P(sum is 7)

Sum 7 possible outcomes = {(1,6), (2,5), (3,4), (4,3), (5,2), (6,1)}

$= P = \displaystyle\frac{6}{36} = \displaystyle\frac{1}{6} = 0.167$

b) P(sum is 11)

Sum 11 possible outcomes = {(5,6), (6,5)}

$= P = \displaystyle\frac{2}{36} = \displaystyle\frac{1}{18} = 0.056$

c) P( sum is 7 or sum is 11)

$= P(\text{sum is 7}) + P(\text{sum is 11}) - (P(\text{sum is 7}\cap \text{sum is 11})) \\= \displaystyle\frac{6}{36} + \displaystyle\frac{2}{36} + 0\\\\= \displaystyle\frac{8}{36} = \displaystyle\frac{2}{9} = 0.223$