Answer:
11 kg
Explanation:
Given weight in kg ∝ d² where d is the distance of the object from the center of the earth
We can write this as an equatio
w = (k/d²) where is a constant
On the surface of the earth, d = 600, w = 80 so we get
80 = k/600² ==> k = 600² ( 80) = 600 x 600 x 80 (1)
At 1000 km altitude, the actual distance of the astronaut from the center of the earth is 1000 + 600 - 1600 km
So we get another equation w' = k/1600²
were w' is the weight of the astronaut at an altitude of 1000km
Using the value of k from (1) we get
w' = (600 x 600 x 80)/(1600 x 1600) = 11.25kg = 11 correct to the nearest kg
Answer: Tine solved 15 hard puzzles.
Explanation:
By applying Pythagorean' theorem, the value of tanP is equal to 3/4.
<h3>How to determine the value of tan P?</h3>
Since triangle PQR has right-angle Q and sinR = 4/5, we have:
sinR = Opp/hyp = 4/5
tanP = Opp/Adj = QR/4
Next, we would determine the length of QR by applying Pythagorean' theorem:
PR² = QR² + PQ²
5² = QR² + 4²
25 = QR² + 16
QR² = 25 - 18
QR = √9
QR = 3 units.
For the value of tanP, we have:
tanP = 3/4.
Read more on Pythagorean theorem here: brainly.com/question/23200848
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The analysis above describes what Dribbling skill.
<h3>What is Dribbling in soccer?</h3>
Dribbling is known to be the act of moving the ball very carefully forward through the act of controlling it with one's feet
This is known to be a very common technique or skills in football. The act of Dribbling is very systematic and it requires skills.
See options below
A.Trapping
B.Scoring
C.Dribbling
D.Kicking
Learn more about soccer from
brainly.com/question/12597997
