1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
SashulF [63]
3 years ago
10

HELP PLS ITS DUE TOMMAROW ILL GIE BRAINLIST FOR THE CORRECT ANSWER

Mathematics
1 answer:
Tasya [4]3 years ago
4 0
You just need to make them all the same common denominator. do you still need help?
You might be interested in
8.Find the value of c that makes the expression be a perfect square trinomial p^2-30p+c
Darina [25.2K]
Hope this is the right one.

Problem 8
p^2 - 30p + c
<em>Step One</em>
Take 1/2 of - 30
1/2 * -30 = - 15

<em>Step 2
</em>Square -15
(-15)^2 = 225
c = 225

Problem Nine
\text{x = }\dfrac{ -b \pm \sqrt{b^{2} - 4ac } }{2a} &#10;
a = 1
b = 4
c = -15
\text{x = }\dfrac{ -4 \pm \sqrt{4^{2} - 4*1*(-15) } }{2*1}
\text{x = }\dfrac{ -4 \pm \sqrt{\text{16} + \text{60} } }{2}

x = [-4 +/- sqrt(76)] / 2
x = [-4 +/- 2*sqrt19]/2
x = [-4/2 +/- 2/2 sqrt[19]
x = - 2 +/- sqrt(19) 

x1 = - 2 + sqrt(19)
x2 = -2 - sqrt(19)

These two can be broken down more by finding the square root. I will leave them the way they are.  It's just a calculator question if you want it to go into decimal form.

Problem Ten

a = 1
b = 4
c = -32

The discriminate is sqrt(b^2 - 4ac)
D = sqrt(b^2 - 4ac)
D = sqrt(4^2 - 4(1)(-32)
D = sqrt(16 - - 128)
D = sqrt(16 + 128)
D = sqrt(144)
D = +/- 12

Since D can equal + or minus 12 there must be 2 possible (and different) roots. As a matter of fact, this quadratic can be factored.
(x + 8)(x - 4) = y 
But that' s not what you were asked for.
The discriminate is >  0 so the roots are going to be real.
<em>Answer; The discriminate is > 0 so there will be 2 real different roots.</em>

4 0
3 years ago
Using the given zero, find one other zero of f(x). Explain the process you used to find your solution.
IRISSAK [1]

Answer:

One other zero is 2+3i

Step-by-step explanation:

If 2-3i is a zero and all the coefficients of the polynomial function is real, then the conjugate of 2-3i is also a zero.

The conjugate of (a+b) is (a-b).

The conjugate of (a-b) is (a+b).

The conjugate of (2-3i) is (2+3i) so 2+3i is also a zero.

Ok so we have two zeros 2-3i and 2+3i.

This means that (x-(2-3i)) and (x-(2+3i)) are factors of the given polynomial.

I'm going to find the product of these factors (x-(2-3i)) and (x-(2+3i)).

(x-(2-3i))(x-(2+3i))

Foil!

First: x(x)=x^2

Outer: x*-(2+3i)=-x(2+3i)

Inner:  -(2-3i)(x)=-x(2-3i)

Last:  (2-3i)(2+3i)=4-9i^2 (You can just do first and last when multiplying conjugates)

---------------------------------Add together:

x^2 + -x(2+3i) + -x(2-3i) + (4-9i^2)

Simplifying:

x^2-2x-3ix-2x+3ix+4+9  (since i^2=-1)

x^2-4x+13                     (since -3ix+3ix=0)

So x^2-4x+13 is a factor of the given polynomial.

I'm going to do long division to find another factor.

Hopefully we get a remainder of 0 because we are saying it is a factor of the given polynomial.

                x^2+1

              ---------------------------------------

x^2-4x+13|  x^4-4x^3+14x^2-4x+13                    

              -( x^4-4x^3+ 13x^2)

            ------------------------------------------

                                 x^2-4x+13

                               -(x^2-4x+13)

                               -----------------

                                    0

So the other factor is x^2+1.

To find the zeros of x^2+1, you set x^2+1 to 0 and solve for x.

x^2+1=0

x^2=-1

x=\pm \sqrt{-1}

x=\pm i

So the zeros are i, -i , 2-3i , 2+3i

7 0
3 years ago
What is the end of your proof? (What are you proving?)
AnnyKZ [126]

Answer

with

Step-by-step explanation:

Statement      Reasons

1.∠1 ≅ 4             Given

2.∠1 = ∠2           Being Vertically opposite angles.

3.∠4 = ∠3          Being Vertically opposite angles.  

4.∠2 = 3             From Statement no 2 & 3, Transitive property.

5.∠2 ≅ 3            From Statement 4

Proved.

6 0
2 years ago
Hi does anyone know this it is important please help me due tonight i will do anything
Inessa [10]

Answer:

$20

Step-by-step explanation:

Total cost of items bought

= $31.21 +$12.75 +$13.25

= $57.21

Remaining cost after paying $40

= $57.21 -$40

= $17.21

Amount borrowed

= change +$17.21

= $2.79 +$17.21

= $20

4 0
2 years ago
Read 2 more answers
kylee bought a pack of 12 cookies. one-third if the cookies are peanut butter. How many of the cookies in the pack are peanut bu
IceJOKER [234]

Answer:

The number of packs are peanuts butter are 4 .

Step-by-step explanation:

As given

Kylee bought a pack of 12 cookies.

one-third if the cookies are peanut butter.

Thus

Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\times Total\ number\ of\ packs

Number\ of\ packs\ of\ peanuts\ butter = \frac{1}{3}\time 12

Number\ of\ packs\ of\ peanuts\ butter = \frac{12}{3}

Number of packs are peanut butter = 4

Therefore the number of packs are peanuts butter are 4 .

4 0
3 years ago
Read 2 more answers
Other questions:
  • Solve for s. 2|s| = 18
    14·1 answer
  • Pleses help me thank you
    13·1 answer
  • Determine which two equations have nonlinear graphs.
    14·1 answer
  • You roled a fair 6 sised die what is p(roll a 2
    13·1 answer
  • How many arrangements of three digits can be formed from the digits zero through nine
    6·1 answer
  • 6 divide 2832 <br> Help me. Idk the answer
    8·2 answers
  • What is the value (Shown in the picture) of f(81)?
    8·1 answer
  • Please answer the image below
    6·1 answer
  • William bought 5 rulers for $7.50. If r represents the cost of one ruler, which equation represents this situation?
    15·1 answer
  • Margaret is reading a book. The number of pages she has left to read is 276−35d, where d represents the number of days she has b
    5·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!