Remark
The quick answer is C does not represent a function. It has two y values for x = 2. These two points are (2,1) and (2,3). That eliminates C. No x can have 2 y values and be called a function. A function can have many x vales for a single y and still be a function.
A has all different x values, so it could be classed as a function. There are no values where x has more than 1 y value.
B also has all different x values. It too is a function.
Answer
A and B are both functions. C is not.
D <<<<< Answer
Answer: option 2 describes best
Step-by-step explanation:Given Marisol grouped the terms and factored the GCF out of the groups of the polynomial 6x3 – 22x2 – 9x + 33. Her work is shown.
Step 1: (6x3 – 22x2) – (9x + 33)
Step 2: 2x2(3x – 11) – 3(3x + 11)
Marisol noticed that she does not have a common factor. Which accurately describes what Marisol should do next?
Marisol should realize that her work shows that the polynomial is prime.
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) – (9x – 33).
Marisol should go back and group the terms in Step 1 as (6x3 – 22x2) + (9x – 33).
Marisol should refactor the expression in Step 2 as 2x2(3x + 11) – 3(3x + 11).
According to question Marisol grouped the terms and has done factorisation of the given polynomial 6x^3 – 22x^2 – 9x + 33.
In step 1 she has written as (6x^3 – 22x^2) – (9x + 33)
Marisol has to go to step 1 in order to correct her mistake. She has to group the expression as (6x^3 – 22x^2) – (9x – 33) so that she will be able to get the expression as
6x^3 – 22x^2 – 9x + 33 after opening the brackets.
Answer:
yes it is hard
Step-by-step explanation:
Most people don’t really learn statistics until they start analyzing data in their own research.
Answer:
(7 , 7.75)
Step-by-step explanation:
Y=1 and x=2 because 2+1=3 and 2(x) plus 3(y) is 5
