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IgorLugansk [536]
2 years ago
11

Help me out with this

Mathematics
1 answer:
trapecia [35]2 years ago
5 0
I would assume that the answer is A.
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In circle J with m \angle HJK= 92m∠HJK=92 and HJ=9HJ=9 units find area of sector HJK. Round to the nearest hundredth.
Diano4ka-milaya [45]

Answer:

65.03square units.

Step-by-step explanation:

Find the diagram in the attachment below.

Area of the sector HJK = theta/360° × πr²

theta is the angle subtended by the sector = ∠HJK = 92°

r is the radius = HJ = 9units.

Substituting the given values in the formula:

Area of sector HJK = 92°/360° × π(9)²

Area of sector HJK = 23,399.28/360

Area of sector HJK = 65.03 square units to nearest hundredth

6 0
3 years ago
Whats the quotient 2x − 3 x ÷ 7 x2
Pavlova-9 [17]

Answer:

the quotient is another word for division so the quotient in this equation is:

2x − 3 x ÷ 7 x2

6 0
3 years ago
CONVERT TO SCIENTIFIC NOTATION:
Otrada [13]
1)1.082*10^9
2)1.496*10^8
3)2.2794*10^8
4)7.784*10^5
5)1.4236*10^9
6)2.867*10^9
7)4.4884*10^9
Hope it helped!
6 0
3 years ago
Please need urgent help. It's my final question. I'll have be brainliest!!
Alecsey [184]
X=32

All triangles add up to 180 degrees so if the right angle is 90 degrees then you have 90 degrees left. Next, you take the 2x and x-6 and plug them into the equation 3x-6=90. Once you solve that you get x=32.
8 0
3 years ago
How do you break down this problem?
ozzi
What do you mean
Could you please insert an equation or a problem
8 0
3 years ago
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