Which statement is true regarding the graphed

Help? I dont remember how to do this!!!!<br><br>

Vesnalui [34]

Answer:

13. 5^7

14. 7^1000

15. 16^10000

25 x 10 x 10 x 10 x 10 x 10 x 10

Step-by-step explanation:

4 0

2 years ago

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Select yes or no to indicate whether a zero must be written in the dividend to find the quotient

neonofarm [45]

Answer:

2.25 divided by 0.6 : Yes and 5.2 divided by 8, 3.63 divided by 3, 71.1 divided by 9 : No

Step-by-step explanation:

We have that when two numbers are divided, they can be written in the form $\frac{p}{q}$ , where p is the dividend and q is the divisor.

Now, when we divide 5.2 by 8, we can write $\frac{5.2}{8}$

Also, the division 3.63 by 3, can be written as $\frac{3.63}{3}$ = 1.21

Further, when we divide 71.1 by 3, we can write $\frac{71.1}{3}$ = 23.7

We can see that above divisions are easy divisions and do not require to write any type of 0 in the numerator.

Moreover, when we divide 2.25 by 0.6, we can write $\frac{2.25}{0.6}$ = $\frac{2.25\times 10}{6}$ .

So, we get that in the last division, we need to write a zero in order to multiply the numerator with 10 for easy division.

Hence, 2.25 divided by 0.6 : Yes and 5.2 divided by 8, 3.63 divided by 3, 71.1 divided by 9 : No

3 0

3 years ago

PLEASE HELP! The table shows the number of championships won by the baseball and softball leagues of three youth baseball divisi

Irina18 [472]

Answer:

Question 1: $P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16}}{ \frac{4}{16}} = \frac{1}{2}$

Question 2:

A. $P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

B. $P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

C. $P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

Step-by-step explanation:

Conditional probability is defined by

$P(A|B)= \frac{P(A and B)}{P(B)}$

with P(A and B) beeing the probability of both events occurring simultaneously.

Question 1:

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( B | Y ) = \frac{ P ( B and Y)}{ P (Y)} = \frac{ \frac{2}{16} }{ \frac{4}{16} } = \frac{1}{2}$

Question 2.A:

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( B and Y)= \frac{ 2 }{ 16 }[/tex]

By definition,

$P ( Y | B ) = \frac{ P(Y and B) }{ P(B) } = \frac{ \frac{2}{16} }{ \frac{6}{16} } = \frac{1}{3}$

Question 2.B:

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

then

P( Z and B)= \frac{ 1 }{ 16 }[/tex]

By definition,

$P( Z | B ) = \frac{ P ( Z and B)}{ P (B)}= \frac{ \frac{1}{16} }{ \frac{6}{16} } = \frac{1}{6}$

Question 3.B

Y: Championships won by the 10 - 12 years old, beeing

$P ( Y)= \frac{ 4 }{ 16 }$

Z: Championships won by the 13 - 15 years old, beeing

$P ( Z)= \frac{ 1 }{ 16 }$

then

$P (Y or Z) = P(Y) + P(Z) = \frac{6}{16}$

B: Baseball League Championships won, beeing

$P ( B ) = \frac{ 6 }{16}$

so

$P((YorZ) and B)= \frac{3}{16}$

By definition,

$P((Y or Z)|B) = \frac{ P ((Y or Z) and B)}{P(B)}= \frac{ \frac{3}{16}}{ \frac{6}{16}}= \frac{1}{2}$

3 0

3 years ago

Pls tell the answer fast please

jekas [21]

Answer:

If I had to take an educated guess I'd say 126° but I'm not 100% sure.

7 0

3 years ago

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Evaluate the following expression.

melisa1 [442]

Answer:

40

Step-by-step explanation:

y = 4

z = 2

8y + 12 - 2z

8(4) + 12 - 2(2)

32 + 12 - 4

44 - 4

40

8 0

3 years ago

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