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Varvara68 [4.7K]

3 years ago

5

How are laws and regulations different from one another? A, Laws are long-standing, while regulations can be modified quickly La

ws are long-standing, while regulations can be modified quickly B, Laws can be modified quickly, while regulations are long-standing Laws can be modified quickly, while regulations are long-standing C, Laws are governed by the federal government while regulations are governed by the state government Laws are governed by the federal government while regulations are governed by the state government D, Violators of laws are taken to criminal court while violators of regulations are taken to civil court. Violators of laws are taken to criminal court while violators of regulations are taken to civil court.

2 answers:

vichka [17]3 years ago

8 0

Answer:

Terms in this set (18)

Original

Which agency is responsible for managing Florida's hunting laws and regulations?

*The Fish & Wildlife Conservation Commission

*The US Fish & Wildlife Service

*The International Hunter Education Association

*The National Rifle Association

The Fish & Wildlife Conservation Commission

How are laws and regulations different from one another?

*Laws are long-standing, while regulations can be modified quickly

*Laws can be modified quickly, while regulations are long-standing

*Laws are governed by the federal government while regulations are governed by the state government

*Violators of laws are taken to criminal court while violators of regulations are taken to civil court.

Laws are long-standing, while regulations can be modified quickly

Why were hunting laws and regulations initially enacted?

*To help market hunters get enough game to survive

*To protect wildlife from over hunting and market hunting

*To help hunters get a fair price for food from wild game

*To protect wildlife from fair chase and conservation efforts

To protect wildlife from over hunting and market huntingExplanation:

Fantom [35]3 years ago

4 0

Thereare 18 terms and the answer is
TERMS 18

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O2 is true.

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4 years ago

A diesel engine with CR= 20 has inlet at 520R, a maximum pressure of 920 psia and maximum temperature of 3200 R. With cold air p

Stella [2.4K]

Answer:

Cut-off ratio $\dfrac{V_3}{V_2}=6.15$

Cxpansion ratio $\dfrac{V_4}{V_3}=3.25$

The exhaust temperature $T_4=1997.5R$

Explanation:

Compression ratio CR(r)=20

$\dfrac{V_1}{V_2}=20$

$P_2=P_3=920 psia$

$T_1=520 R ,T_{max}=T_3,T_3=3200 R$

We know that for air γ=1.4

If we assume that in diesel engine all process is adiabatic then

$\dfrac{T_2}{T_1}=r^{\gamma -1}$

$\dfrac{T_2}{520}=20^{1.4 -1}$

$T_2=1723.28R$

$\dfrac{V_3}{V_2}=\dfrac{T_3}{T_2}$

$\dfrac{V_3}{V_2}=\dfrac{3200}{520}$

So cut-off ratio $\dfrac{V_3}{V_2}=6.15$

$\dfrac{V_1}{V_2}=\dfrac{V_4}{V_3}\times\dfrac{V_3}{V_2}$

Now putting the values in above equation

$\dfrac20=\dfrac{V_4}{V_3}\times 6.15$

$\dfrac{V_4}{V_3}=3.25$

So expansion ratio $\dfrac{V_4}{V_3}=3.25$ .

$\dfrac{T_4}{T_3}=(expansion\ ratio)^{\gamma -1}$

$\dfrac{T_3}{T_4}=(3.25)^{1.4 -1}$

$T_4=1997.5R$

So the exhaust temperature $T_4=1997.5R$

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4 years ago

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Answer:

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Explanation:

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B) The preferred production system here will be Batch shop production because the manufacturer produces Gaskets and they are of different styles hence he needs to produce them in batches

C) Job shop production

D) production here is streamlined to a particular ( tablet form ) hence the production system here would be a Production line system of production

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3 years ago

A 0.66 ft steel bar undergoes a stretch of 0.75 in in an axial direction. What is the strain? Use three significant figures (fou

Lapatulllka [165]

Answer:

The strain is 0.0947.

Explanation:

Strain is the ration of change in dimension to the original dimension under application of load. Depending upon load, the bar may stretch or compress. So, the strain can be negative in case of compression or positive in case of tension.

Step1

Given:

Original length of the steel bar is 0.66 ft or 7.92 in.

Stretch in the bar is of 0.75 in.

Calculation:

Step2

Strain is calculated as follows:

$e=\frac{\bigtriangleup l}{l_{o}}$

$e=\frac{0.75}{7.92}$

e = 0.0947

Positive sign is for stretching condition of the bar.

Thus, the strain is 0.0947.

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