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TiliK225 [7]
2 years ago
15

Trigonometry

Mathematics
1 answer:
Mashcka [7]2 years ago
3 0

The area of the triangle EFG is 7.4 square units.

Explanation:

Given that the measurements of the sides of the triangle are EF = 8, EG = 8 and m\angle E=22^{\circ}

We need to determine the area of the triangle EFG

<u>Area of the triangle:</u>

The area of the triangle EFG can be determined using the formula,

\text {Area}=\frac{1}{2} fg \sin E

Substituting the values, we get,

\text {Area}=\frac{1}{2} (5)(8) \sin 22^{\circ}

Simplifying the values, we have,

\text {Area}=\frac{1}{2}(40)(0.37)

Multiplying, we get,

\text {Area}=\frac{14.8}{2}

Dividing, we get,

\text {Area}=7.4

Hence, the area of the triangle EFG is 7.4 square units.

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John's current salary is 40000 per year.His annual pay raise is always a percent of his salary.What would his salary be if he re
ad-work [718]

Answer:

The salary after four consecutive increase = $ 46794.34

Step-by-step explanation:

According to question,

salary of MR. John = $ 40000 per year

percentage py increase = 4%

Let the salary after four consecutive pay increase = x

So, X = 40000 (1 +\frac{4}{100})^4

Or, X = 40000 (\frac{26}{25})^4

Or, X = 46794.34

Hence the salary increase after four consecutive pay increase at 4% = $46794.34  Answer

3 0
3 years ago
Describe and correct the error a student made in finding the midpoint cd with c(-4,5) and d(-1,-4).
Gnesinka [82]

Answer:

Step-by-step explanation:

The formula for finding the midpoint of two coordinates is expressed as;

M(X,Y) = (\frac{x_1+x_2}{2} , \frac{y_1+y_2}{2})

Given the coordinates c(-4,5) and d(-1,-4), x1 = -4, y1 = 5, x2 = -1 and y2 = -4.

For the X coordinate of the midpoint

X = x1+x2/2

X = -4+(-1)/2

X = -4-1/2

X = -5/2

X = -2.5

Similarly for Y:

Y = y1+y2/2

Y = 5+(-4)/2

Y = 5-4/2

Y = 1/2

Y = 0.5

Hence the midpoint coordinate of C(-4,5) and D (-1,-4) is (-2.5, 0.5)

5 0
3 years ago
Laurel wants to build a fence around her square garden. Each side measures 50 feet. She also wants to fence in 3 square rose bed
Rufina [12.5K]
Laurel needs 210.5 feet of fence
3 0
3 years ago
20 POINTS!!! PLEASE HELP!!!
alex41 [277]

Answer:

Option 2

Step-by-step explanation:

It's a rotation

7 0
2 years ago
Read 2 more answers
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
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