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DaniilM [7]
3 years ago
6

Help asap no wrong answers pls

Mathematics
2 answers:
a_sh-v [17]3 years ago
5 0

Answer:

Exactly one solution

Step-by-step explanation:

Because they two lines dont have the same slope, they must have only one solution.

Murljashka [212]3 years ago
4 0
Exactly one solution :))))))))))
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Simplify the following expression completely, where x is greater than or equal too 0.
Dennis_Churaev [7]
First you want the numbers under the radical to be the same so you can combine like terms.

x \sqrt{5xy^4} =x \sqrt{5x*^4y} = xy^2 \sqrt{5x}
\sqrt{405x^3y^4} =  \sqrt{5x*81x^2y^4} =9xy^2 \sqrt{5x}
\sqrt{80x^3y^4} =  \sqrt{5x*16x^2y^4} = 4xy^2 \sqrt{5x}

Now add together to get 14xy^2 \sqrt{5x}
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Sarah buys a shirt on sale at
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$20.58

Step-by-step explanation:

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Jose deposited $750 into an account that earned 12% simple interest over 6 years. What is the amount of interest earned after 6
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3 years ago
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Does this diverge or converge?
olga2289 [7]

Answer:

L = 7/6 , and the correct option is B, the series diverges.

Step-by-step explanation:

Here we have that:

an = \frac{(3n + 3)*7^n}{6^{n+4}}

Now we want to see the quotient test, then we need to do find the value of the quotient as n tends to infinity. Then we first need to find the quotient:

a(n + 1)/a(n) = \frac{(3(n + 1) + 3)*7^{n + 1}}{6^{n + 1 + 4}}*\frac{6^{n + 4}}{(3*(n) + 3)*7^{n}}

We can simplify the right part to get:

\frac{(3(n + 1) + 3)*7^{n + 1}}{6^{n + 1 + 4}}*\frac{6^{n + 4}}{(3*(n) + 3)*7^{n}}=  \frac{(3n + 3 + 3)*7^{n + 1}}{6^{n + 5}}*\frac{6^{n + 4}}{(3*n + 3)*7^{n}}

\frac{(3n + 3 + 3)*7^{n + 1}}{6^{n + 5}}*\frac{6^{n + 4}}{(3*n + 3)*7^{n}}= \frac{(3n + 3 + 3)*7}{(3*n + 3)*6}

Now we want to find the limit of this as n goes to infinity, we can see that both parts will tend to infinity, then we need to use the Lhopital rule and find the limit of the quotient of the first derivatives.

The first derivatives are:

For the denominator: (3*6)

For the numerator: (3*7)

Then we need to find the limit as n goes to infinity to:

\frac{3*7}{3*6} = \frac{7}{6}

But this does not depend on the value of n, then the limit is just 6/7.

L = 7/6

And 7/6 > 1.

Then we can conclude that our series diverges.

3 0
3 years ago
How do you even solve these?
arsen [322]
The equation takes the x coordinate of the vertex and puts it into an equation in vertex form with the y coordinate and the radius. The radius is entered as its squared value. The general form of a circle is (x-h)^2 + (y-k)^2 = r^2. So yours would look like this: (x-3)^2 + (y+2)^2 = 25
3 0
4 years ago
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