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3 years ago

Write a point-slope equation for the line ?

Mathematics

1 answer:

olga nikolaevna [1]3 years ago

3 0

Answer:

Point-slope equation for the line is

$y-2= -\frac {3}{2} (x -0)$

Step-by-step explanation:

Equation of straight line in slope intercept form is given as

$y-y_1=m(x-x_1)$ ---------- (1)

Here

Slope $m=-\frac{3}{2}$

Any Passing Point $(x_1, y_1) = (0, 2)$

Substituting values in equation (1)

$y-2= -\frac {3}{2} (x -0)$

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What is the volume of the cylinder. its 15 units high and a radius of 11.

murzikaleks [220]

Answer:

V = 1815 pi units ^3

Step-by-step explanation:

The volume of a cylinder is given by

V = pi r^2 h

V = pi ( 11)^2 * 15

V = 1815 pi

8 0

3 years ago

Popcorn was donated for the school fair by 3 different popcorn vendors. They donated a total of 636 bags of popcorn.Each vendor

miv72 [106K]

Answer:

The answer is 212.

Step-by-step explanation:

If there are 3 vendors that donated popcorn, and there are 636 bags, and they all gave the same amount of bags, then you would get the total (636) and divide it by the amount of vendors (3) which would give you 212.

5 0

4 years ago

25222+14945 rounded to the nearest ten

FrozenT [24]

The answer for this problem is 40167.

To round this up to the nearest 10, if the ones is above 5, round it up.

To the nearest 10

40170

6 0

3 years ago

Read 2 more answers

Complete the equation of the line through ( − 1 0 , − 7 ) (−10,−7) and ( − 5 , − 9 ) (−5,−9).

Maksim231197 [3]

The point-slope form:

$y-y_1=m(x-x_1)$

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

We have the points (-10, -7) and (-5, -9). Substitute:

$m=\dfrac{-9-(-7)}{-5-(-10)}=\dfrac{-9+7}{-5+10}=\dfrac{-2}{5}=-\dfrac{2}{5}$

$y-(-7)=-\dfrac{2}{5}(x-(-10))$

$\boxed{y+7=-\dfrac{2}{5}(x+10)}$ point-slope form

$y+7=-\dfrac{2}{5}(x+10)$ use distributive property

$y+7=-\dfrac{2}{5}x-4$ subtract 7 from both sides

$\boxed{y=-\dfrac{2}{5}x-11}$ slope-intercept form

$y=-\dfrac{2}{5}x-11$ multiply both sides by 5

$5y=-2x-55$ add 2x to both sides

$\boxed{2x+5y=-55}$ standard form

3 0

3 years ago

G Find non-zero vectors x and y that are both orthogonaland orthogonal to each other.

Rainbow [258]

Answer:

x = <1,5>

y = <-5,1>

Step-by-step explanation:

Let x, y be two vectors in 2D

defined as:

x = <a, b>

y = <c, d>

for x, y to be orthogonal, we know that their dot or scalar product must be zero so,

x . y = 0

<a, b> . <c, d> = 0

a*c + b*d = 0 ------ (A)

Now, consider any four values for a, b, c, and d respectively which satisfy the equation (A)

i.e. I chose (you can choose on your own choice):

a=1, b=5, c=-5, d=1

Verifying Equation (A):

(1)*(5) + (-5)*(1) =0

5 - 5 = 0

0 = 0 (True)

Therefore,

Our vectors x, y are:

x = <1, 5>

y = <-5, 1>

4 0

4 years ago