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solmaris [256]
3 years ago
11

Complete the following statement.

Mathematics
1 answer:
Svetradugi [14.3K]3 years ago
3 0

Answer:

if p ( x ) = x^2 + 7 x + 3 is divided by x + 4, the remainder is -9

Step-by-step explanation:

We need to find the remainder if p ( x ) = x^2 + 7 x + 3 is divided by x + 4

Dividing p ( x ) = x^2 + 7 x + 3 by x + 4

The division is shown in figure attached.

The remainder = -9

The quotient = x+3

So, if p ( x ) = x^2 + 7 x + 3 is divided by x + 4, the remainder is -9

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Answer:

C because your adding 4 to it I guess

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Given: O ∈ AB , ON is ∠ bisector of ∠AOC, OF is ∠ bisector of ∠COB, m∠FOB=70°. Find: m∠AON
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Answer:

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Step-by-step explanation:

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3 years ago
For each of the following vector fields
olga nikolaevna [1]

(A)

\dfrac{\partial f}{\partial x}=-16x+2y

\implies f(x,y)=-8x^2+2xy+g(y)

\implies\dfrac{\partial f}{\partial y}=2x+\dfrac{\mathrm dg}{\mathrm dy}=2x+10y

\implies\dfrac{\mathrm dg}{\mathrm dy}=10y

\implies g(y)=5y^2+C

\implies f(x,y)=\boxed{-8x^2+2xy+5y^2+C}

(B)

\dfrac{\partial f}{\partial x}=-8y

\implies f(x,y)=-8xy+g(y)

\implies\dfrac{\partial f}{\partial y}=-8x+\dfrac{\mathrm dg}{\mathrm dy}=-7x

\implies \dfrac{\mathrm dg}{\mathrm dy}=x

But we assume g(y) is a function of y alone, so there is not potential function here.

(C)

\dfrac{\partial f}{\partial x}=-8\sin y

\implies f(x,y)=-8x\sin y+g(x,y)

\implies\dfrac{\partial f}{\partial y}=-8x\cos y+\dfrac{\mathrm dg}{\mathrm dy}=4y-8x\cos y

\implies\dfrac{\mathrm dg}{\mathrm dy}=4y

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4 0
3 years ago
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