3 years ago

Solve for x 6x + 5 3x + 13

Mathematics

1 answer:

mixer [17]3 years ago

7 0

Answer:X=6!

Step-by-step explanation:

Your welcome

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the height in feet of an object projected upward is given by the polynomial -16t^2+60t+90 where t represents time, in seconds. F

Karolina [17]

<u>Given</u>:

The height of an object project upward is given by the polynomial

$h=-16t^2+60t+90$

where t represents the time, in seconds.

We need to determine the height after t = 2.5 seconds.

<u>Height of an object:</u>

The height of an object after 2.5 seconds can be determined by substituting t=2.5 in the polynomial, we get;

$h=-16(2.5)^2+60(2.5)+90$

Simplifying, we get;

$h=-16(6.25)+60(2.5)+90$

$h=-100+150+90$

$h=140$

Thus, the height of an object is 140 feet.

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Step-by-step explanation:

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maxonik [38]

Answer:

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Step-by-step explanation:

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(1 point) A particle starts at the point P=(−2,−1,3)P=(−2,−1,3) when t=0t=0 and moves along a straight line toward Q=(−4,0,6)Q=(

Ahat [919]

Answer:

The position is given by r(t) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

Step-by-step explanation:

The direction is given by the difference between the starting point and the end point, thus it is (-4,0,6)-(-2,-1,3) = (-2,1,3). The norm of this vector is √( (-2)²+1²+3²) = √14 = 3.7416 secons

Since the speed is 7 cm/sec, we need to multiply this vector by 7/√14 = √3.5 in order to obtain how much does the particle advance each second.

As a consecuence, it advances (-2,1,3) * √3.5 = (- √14, √3.5, 3 √3.5)

And, as a result, the position after t seconds is given by the function

r(t) = (-2,1,3) + t (-√14, √3.5, 3 √3.5) = (-2 -t √14, 1 + √3.5, 3 + 3√3.5)

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Mr. Mike dropped a 5Kg metal ball and and a 1Kg regular basket ball from 6m height. This demonstration conducted in a perfect Va

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Answer:

ist c both will reach at the same time.

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