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julia-pushkina [17]
3 years ago
7

Answer please its for my finals please

Mathematics
2 answers:
mel-nik [20]3 years ago
6 0
C.8 divided by 3 equals 600
dalvyx [7]3 years ago
5 0

Answer:

Part A: c = 2.25 + b

Part B: c = 6.75, b = 8

hope this helped!

You might be interested in
Subtract 7x^2−5xy+8y^2 from −2x^2−15xy+9y^2
Ghella [55]

Answer:

y^2-10xy-9x^2

Step-by-step explanation:

We want to subtract 7x^2 -5xy+8y^2 from -2x^2-15xy+9y^2.


We set up the subtraction problem as follows:


(-2x^2-15xy+9y^2)-(7x^2-5xy+8y^2).


We expand the brackets to obtain;


=-2x^2-15xy+9y^2-7x^2+5xy-8y^2.


We regroup the terms to obtain;


=9y^2-8y^2-15xy+5xy-2x^2-7x^2.


We now simplify to obtain;


=y^2-10xy-9x^2.





4 0
3 years ago
Look at this graph:
Dmitry_Shevchenko [17]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

5 0
3 years ago
Mark had 3 quarts of milk how many pints of milk did he have
mamaluj [8]
Mark had 6 pints of milk.
7 0
4 years ago
Read 2 more answers
Simplify $\sqrt[3]{1+8} \cdot \sqrt[3]{1+\sqrt[3]{8}}$.
Margaret [11]

Answer:

its hard to read with all the different symbols, but try yawhtam (read backwards. wont let me post the real website) , i hope this helps!

if you just take a picture or screenshot of the problem it will help you simplify!

6 0
4 years ago
A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s. What is the le
Tems11 [23]

Answer:

51.72 cm.

Step-by-step explanation:

We have been given that a pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s. We are asked to find the length of the pipe.

First of all, we will find the wavelength using following formula.

\text{Wave speed}=\text{Frequency}\times \text{Wave length}

331\frac{\text{m}}{\text{s}}=320\text{ Hz}\times \text{Wave length}

We know that Hz is equal to \frac{1}{s}.

331\frac{\text{m}}{\text{s}}=320\frac{1}{\text{s}}\times \text{Wave length}

331\text{ m}=320\times \text{Wave length}

\text{Wave length}=\frac{331}{320}\text{ m}

\text{Wave length}=1.034375\text{ m}

Length of the pipe would be half of the wave-length.

\text{Length of pipe}=\frac{1.034375}{2}\text{ m}=0.5171875\text{ m}

Since the length of pipe is in meters, so we will convert it into cm.

1 m = 100 cm

\text{0.5171875 m}=0.5171875\times 100\text{ cm}=51.71875\text{ cm}\approx 51.72\text{ cm}

Therefore, the length of the pipe would be 51.72 cm.

6 0
4 years ago
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