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3 years ago

Answer please its for my finals please

Mathematics

2 answers:

mel-nik [20]3 years ago

6 0

C.8 divided by 3 equals 600

dalvyx [7]3 years ago

5 0

Answer:

Part A: c = 2.25 + b

Part B: c = 6.75, b = 8

hope this helped!

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Subtract 7x^2−5xy+8y^2 from −2x^2−15xy+9y^2

Ghella [55]

Answer:

$y^2-10xy-9x^2$

Step-by-step explanation:

We want to subtract $7x^2 -5xy+8y^2$ from $-2x^2-15xy+9y^2$ .

We set up the subtraction problem as follows:

$(-2x^2-15xy+9y^2)-(7x^2-5xy+8y^2)$ .

We expand the brackets to obtain;

$=-2x^2-15xy+9y^2-7x^2+5xy-8y^2$ .

We regroup the terms to obtain;

$=9y^2-8y^2-15xy+5xy-2x^2-7x^2$ .

We now simplify to obtain;

$=y^2-10xy-9x^2$ .

4 0

3 years ago

Look at this graph:

Dmitry_Shevchenko [17]

Answer:

3/2

Step-by-step explanation:

slope=rise/run=30/20=3/2

5 0

3 years ago

Mark had 3 quarts of milk how many pints of milk did he have

mamaluj [8]

Mark had 6 pints of milk.

7 0

4 years ago

Read 2 more answers

Simplify $\sqrt[3]{1+8} \cdot \sqrt[3]{1+\sqrt[3]{8}}$.

Margaret [11]

Answer:

its hard to read with all the different symbols, but try yawhtam (read backwards. wont let me post the real website) , i hope this helps!

if you just take a picture or screenshot of the problem it will help you simplify!

6 0

4 years ago

A pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s. What is the le

Tems11 [23]

Answer:

51.72 cm.

Step-by-step explanation:

We have been given that a pipe that is open at both ends has a fundamental frequency of 320 Hz when the speed of sound in air is 331 m/s. We are asked to find the length of the pipe.

First of all, we will find the wavelength using following formula.

$\text{Wave speed}=\text{Frequency}\times \text{Wave length}$

$331\frac{\text{m}}{\text{s}}=320\text{ Hz}\times \text{Wave length}$

We know that Hz is equal to $\frac{1}{s}$ .

$331\frac{\text{m}}{\text{s}}=320\frac{1}{\text{s}}\times \text{Wave length}$

$331\text{ m}=320\times \text{Wave length}$

$\text{Wave length}=\frac{331}{320}\text{ m}$

$\text{Wave length}=1.034375\text{ m}$

Length of the pipe would be half of the wave-length.

$\text{Length of pipe}=\frac{1.034375}{2}\text{ m}=0.5171875\text{ m}$

Since the length of pipe is in meters, so we will convert it into cm.

1 m = 100 cm

$\text{0.5171875 m}=0.5171875\times 100\text{ cm}=51.71875\text{ cm}\approx 51.72\text{ cm}$

Therefore, the length of the pipe would be 51.72 cm.

6 0

4 years ago