3 years ago

A class roster has 30 students, but only 80% of the students are present today. How many students are in class?

Mathematics

1 answer:

emmainna [20.7K]3 years ago

5 0

It is 24 for sureeeee

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Which equations have a negative solution?

UNO [17]

A. w= -22 so A has a negative solution. D doesn't have a variable so I'm not sure about it (did you type it correctly?), but because only one side of the equation has a negative number, I'm guessing D is also a negative solution

8 0

3 years ago

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You had $22 to spend on four raffle tickets. After buying them you had $6. How much did each raffle ticket cost?

ozzi

22-6=16. 16÷4=4. Each ticket costs $4.

6 0

3 years ago

If f(x) = x + 8 and g(x) = x3, what is (gºf)(-5)?

11111nata11111 [884]

Answer:

Step-by-step explanation:

f(-5) = -5 + 8 = 3

g(3) = 3^3 = 27

4 0

4 years ago

Prove the following statement.

gayaneshka [121]

Answer:

You can prove this statement as follows:

Step-by-step explanation:

An odd integer is a number of the form $2k+1$ where $k\in \mathbb{Z}$ . Consider the following cases.

Case 1. If $k$ is even we have: $(2k+1)^{2}=(2(2s)+1)^{2}=(4s+1)^{2}=16s^2+8s+1=8(2s^2+s)+1$ .

If we denote by $m=2s^2+2$ we have that $(2k+1)^{2}=8m+1$ .

Case 2. if $k$ is odd we have: $(2k+1)^{2}=(2(2s+1)+1)^{2}=(4s+3)^{2}=16s^2+24s+9=16s^{2}+24s+8+1=8(2s^{2}+3s+1)+1$ .

If we denote by $m=2s^{2}+24s+1$ we have that $(2k+1)^{2}=8m+1$

This result says that the remainder when we divide the square of any odd integer by 8 is 1.

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3 years ago

Harry pays $540.00 for one dozen collector edition baseball cards. How much does he pay for each baseball card?

astraxan [27]

Answer:

45 dollars

Step-by-step explanation:

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3 years ago