Question

Find the equation of the line passing through the points (3,-2) and (4, 6). y = 8x + [?]

Answer 1

Step-by-step explanation:

1.) Plug in one of the points.

y = 8x + b

6 = 8(4) + b

2.) Solve for b (or [?])

$6 = 32 + b \\ - 32 \: \: \: \: \: \: \: \: \: - 32$

32 cancels out on the right side.

Subtract 32 from 6, which is -26

3.) -26 = b

4.) Check with other point:

-2 = 8(3) + b

-2 = 24 + b

Cancel out 24 on the right side: 24-24 = 0

-2 - 24 = -26

-26 = b