The given matrix is
| 1 6 4 |
| 0 1 2 |
| 0 0 1 |
Create the augmented matrix.
| 1 6 4 | 1 0 0 | R1
| 0 1 2 | 0 1 0 | R2
| 0 0 1 | 0 0 1 | R3
R1 -> R1 - 6*R2
| 1 0 -8 | 1 -6 0 | R1
| 0 1 2 | 0 1 0 | R2
| 0 0 1 | 0 0 1 | R3
R1 -> R1 + 8*R3
| 1 0 0 | 1 -6 8 | R1
| 0 1 2 | 0 1 0 | R2
| 0 0 1 | 0 0 1 | R3
R2 -> R2 - 2*R3
| 1 0 0 | 1 -6 8 |
| 0 1 0 | 0 1 -2 |
| 0 0 1 | 0 0 1 |
The inverse is
| 1 -6 8 |
| 0 1 -2 |
| 0 0 1 |
Verification:
| 1 6 4 | | 1 -6 8 | | 1 0 0 |
| 0 1 2 | | 0 1 -2 | = | 0 1 0 |
| 0 0 1 | | 0 0 1 | | 0 0 1 |
Answer:
x² + 4x - 12, remainder - 60
Step-by-step explanation:
Using synthetic division to divide
Since dividing by x - 1, evaluate for x = 1
1 | 1 3 - 16 - 48
↓ 1 4 - 12
---------------------------
1 4 - 12 - 60 ← degree 2 polynomial
quotient = x² + 4x - 12, remainder = - 60
Hence
= x² + 4x - 12 - ![\frac{60}{x-1}](https://tex.z-dn.net/?f=%5Cfrac%7B60%7D%7Bx-1%7D)
If You know how to do long division then... You move the decimal that’s outside the house to where it’s not there no more then divide . Or turn the decimals into Fractions and do the reciprocal.
I put the equation in my graphing calculator and looked at the table.
It seems the zeroes are:
(-2,0) and (5,0)... I'm not really sure about the last one, I'm sorry
Hello,
The answer is x= y-13 / 2 ( everything after the x= is a fraction)
How to solve;
Start by subtracting 13 from both sides of y=2x+13, we do this to get the x on 1 side
So now we have y-13=2x
Next divide both sides by 2, we do this to get x by it self.
y-13/2=x
Now we flip the problem and there you have it!
Edit: The x does not have a Pos or neg value, The only way to know what x is, is to solve for x.