Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
<h3>What is the distance?</h3>
Distance is the movement of an object regardless of direction. The distance can be defined as the amount of length an object has covered, regardless of its starting or ending position
We know that r × t = d
r = rate of speed
t = time
d = distance
For the motor boat
9 × t = d = rate × time
For the tour boat
27 × (t - 2) = d = rate × time
When they both cover the same distance in the same amount of time, they will eventually cross paths.
They both cover the same d-mile distance, so:
9 ×t = 27 × (t - 2)
Simplify to get:
9 × t = 27 × t - 54
18 t = 54
t = 3
The motor boat will have traveled at 9 mph for 3 hours to make a distance of 9 × 3 = 27 miles.
The tour boat will have traveled at 27 mph for 1 hour to make a distance of 1 × 27 = 27 miles.
Since the motor boat left the dock 2 hours before the tour boat, their meeting point will be 27 miles from the dock from which both boats departed after 3 hours.
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Answer:
the answer is d
Step-by-step explanation:
1. Place your compass point on X and measure the distance to point Y. Swing an arc of this size above (or below) the segment.
2. Without changing the span on the compass, place the compass point on Y and swing the same arc, intersecting with the first arc.
3. Label the point of intersection as the third vertex of the equilateral triangle.
4. Use you straight edge and connect the points.
Answer:
x=0, y=-5
Step-by-step explanation:
The system is
(1) 5x+3y=-15
(2) -8x-2y=10
Let's solve it by elimination. In order to do it, you have to multiply the equations by suitable numbers in such a way that when you add the 2 equations, one of the unknowns is eliminated
Multiply (1) by 2 and (2) by 3
(1) 10x+6y=-30
(2) -24x-6y=30
Add the two equations
10x-24x+6y-6y=-30+30 ----> -14x=0---->x=0
Now replace this value in any equation, for example in (1)
6y=-30 ----> y=-30/6----> y=-5
