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ludmilkaskok [199]
3 years ago
5

Juan went out to eat dinner, and the meal cost $60.00. If Juan received a 18% discount, what was the total value of the discount

?
Mathematics
2 answers:
NikAS [45]3 years ago
6 0
The discount took out $10.2
Pachacha [2.7K]3 years ago
3 0

Answer:

$49.2

Step-by-step explanation:

Hope i actually helped.

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The answer to your questions would be “46 degrees” :) you’re welcome
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2 years ago
A manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective
andriy [413]

Answer:

(a) P(X \leq 20) = 0.9319

(b) Expected number of defective light bulbs = 15

(c) Standard deviation of defective light bulbs = 3.67

Step-by-step explanation:

We are given that a manufacturer of Christmas light bulbs knows that 10% of these bulbs are defective. It is known that light bulbs are defective independently. A box of 150 bulbs is selected at random.

Firstly, the above situation can be represented through binomial distribution, i.e.;

P(X=r) = \binom{n}{r} p^{r} (1-p)^{2} ;x=0,1,2,3,....

where, n = number of samples taken = 150

            r = number of success

           p = probability of success which in our question is % of bulbs that

                  are defective, i.e. 10%

<em>Now, we can't calculate the required probability using binomial distribution because here n is very large(n > 30), so we will convert this distribution into normal distribution using continuity correction.</em>

So, Let X = No. of defective bulbs in a box

<u>Mean of X</u>, \mu = n \times p = 150 \times 0.10 = 15

<u>Standard deviation of X</u>, \sigma = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.7

So, X ~ N(\mu = 15, \sigma^{2} = 3.7^{2})

Now, the z score probability distribution is given by;

                Z = \frac{X-\mu}{\sigma} ~ N(0,1)

(a) Probability that this box will contain at most 20 defective light bulbs is given by = P(X \leq 20) = P(X < 20.5)  ---- using continuity correction

    P(X < 20.5) = P( \frac{X-\mu}{\sigma} < \frac{20.5-15}{3.7} ) = P(Z < 1.49) = 0.9319

(b) Expected number of defective light bulbs found in such boxes, on average is given by = E(X) = n \times p = 150 \times 0.10 = 15.

Standard deviation of defective light bulbs is given by = S.D. = \sqrt{np(1-p)} = \sqrt{150 \times 0.10 \times (1-0.10)} = 3.67

8 0
3 years ago
Identify the function as a power function, a polynomial function, or neither.<br><br> f(x)=4(x^3)^3
Alborosie

Answer:7

Step-by-step explanation:7

7 0
3 years ago
Jake took out an interest-free loan of $3,011.70 from the bank to buy a car. He paid the bank $200.78 each month until it was pa
trasher [3.6K]
$200.78 multiplied by 15 equals <span>$3,011.70. So your answer is D)</span>
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3 years ago
John has 12 pounds of dog food and is going to separate it into 3/4 pound portions. How many portions of dog food will he have?
NNADVOKAT [17]

16 portions

explanation:

12 / 3/4

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= 4*4 = 16

7 0
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