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3 years ago

Distribute and simplify: 2(h - 4)

Mathematics

2 answers:

STatiana [176]3 years ago

8 0

Answer: 2h- 8

Step-by-step explanation:

vesna_86 [32]3 years ago

8 0

Answer:

2h-8

Step-by-step explanation:

Simplify

Distribute

2 ( ℎ − 4 )

2 ℎ − 8

Solution

2 ℎ − 8

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In a particular class of 22 students, 16 are men. What fraction of the students in the class are men?

kati45 [8]

If there counting man as students then its 16/22
If there not counting them as students then it 16/38

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3 years ago

What is the domain of the function shown in the graph below? answer type: interval, all real values except one, all real values

enot [183]

Answer: the domain is negative infinity to positive infinity

Step-by-step explanation:

the graph covers all x values

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4 years ago

Read 2 more answers

a computer costs $849.75 and the hard drive is 61.3% of the total cost what is a reasonable estimate for the cost of the hard dr

kati45 [8]

Answer:

$510 you get this answer by first rounding $849.75 to $850 and rounding 61.3% to 60% then multiply $850 and .6 to get your answer $510

Step-by-step explanation:

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3 years ago

For this problem, carry at least four digits after the decimal in your calculations. Answers may vary slightly due to rounding.

zhannawk [14.2K]

Answer:

a) 0.6032

Lower limit: 0.48

Upper limit: 0.72

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of $\pi$ , and a confidence level of $1-\alpha$ , we have the following confidence interval of proportions.

$\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}$

In which

z is the zscore that has a pvalue of $1 - \frac{\alpha}{2}$ .

Question a:

In a random sample of 63 professional actors, it was found that 38 were extroverts.

We use this to find the sample proportion, which is the point estimate for p. So

$\pi = \frac{38}{63} = 0.6032$

Question b:

Sample of 63 means that $n = 63$

95% confidence level

So $\alpha = 0.05$ , z is the value of Z that has a pvalue of $1 - \frac{0.05}{2} = 0.975$ , so $Z = 1.96$ .

The lower limit of this interval is:

$\pi - z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6032 - 1.96\sqrt{\frac{0.6032*0.3968}{63}} = 0.4824$

The upper limit of this interval is:

$\pi + z\sqrt{\frac{\pi(1-\pi)}{n}} = 0.6032 + 1.96\sqrt{\frac{0.6032*0.3968}{63}} = 0.724$

Rounding to two decimal places:

Lower limit: 0.48

Upper limit: 0.72

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3 years ago

Suppose that a random sample of 50 bottles of a particular brand of cough syrup is selected and the alcohol content of each bott

timofeeve [1]

Answer:

95% confidence interval will be narrower.

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 50

95% confidence interval for average alcohol content:

$(7.8, 9.4)$

a) 90% confidence interval

If we calculate a 90% confidence interval, then the confidence interval become narrower because we decreased the confidence percentage.

This would decrease the margin of error.

Hence, the confidence interval become narrower.

6 0

3 years ago