Answer:
def remove_duplicates(lst):
no_duplicate = []
dup = []
for x in lst:
if x not in no_duplicate:
no_duplicate.append(x)
else:
dup.append(x)
for y in dup:
if y in no_duplicate:
no_duplicate.remove(y)
return no_duplicate
Explanation:
Create a function called remove_duplicates that takes one parameter, lst
Create two lists one for no duplicate elements and one for duplicate elements
Create for loop that iterates through the lst. If an element is reached for first time, put it to the no_duplicate. If it is reached more than once, put it to the dup.
When the first loop is done, create another for loop that iterates through the dup. If one element in no_duplicate is in the dup, that means it is a duplicate, remove that element from the no_duplicate.
When the second loop is done, return the no_duplicate
<span>IDE but how old is this text you quote this passage from? Because IDE has had its day, and that day is over. SATA has replaced IDE as the connection of choice for storage (hard drives/SSD's/optical drives). You can't buy anything with IDE connections on the motherboard anymore, although you can still find IDE drives if you look hard enough.</span>
There are reasons why a statement can be wrong. The option that is a wrong statement is Since 2015, the number of unfilled cybersecurity positions has increased by 10 percent.
<h3>How are many cybersecurity jobs unfilled?</h3>
The U.S. is known to have a high total employed cybersecurity workforce and some that are unfilled positions as reported by Cyber Seek.
Studies has shown that since 2015, the number of unfilled cybersecurity positions has gone up by 50 percent. Such that the total expected rate has been approximated to be at 1.8 million open cybersecurity positions by 2022.
Learn more about cybersecurity from
brainly.com/question/14286078
Answer:
a web browser ie firefox, chrome , safari
Explanation:
Answer: try to just add as little as possible then add the answser or just reload your browser
Explanation: