Question

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Answer 1

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$x^2+10x+25=0\\\\(x)^2+2.x.5+(5)^2\\\\(x+5)^2$

• one solution

$x^2+5x=0\\\\x(x+5)=0\\\\x=0,x+5=0$

• two solution

$x^2-10x+25=0\\\\(x)^2-2.x.5+(5)^2\\\\(x-5)^2$

• one solution

$x^2-25=0\\\\x^2=25\\\\x= \binom{ + }{ - }5$

• two solution

Answer 2

Answer:

see below

Step-by-step explanation:

x^2 + 10x+25 =0

This is the sum of squares

(x+5)^2 =0

x = -5   one solution

x^2 +5x = 0

x(x+5) = 0

x=0   x=-5   two solutions

x^2 -10x +25 = 0

This is the difference of squares

(x-5)^2 = 0

x=5   one solution

x^2 -25 =0

x^2 = 25

x = ±5   two solutions