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In-s [12.5K]
4 years ago
5

Mr. Hudkins wants his 6th grade math class to memorize their multiplication facts. He decides to increase the number of facts th

ey are expected to memorize each week and creates the following table.
Week
(w) Number of Multiplication Facts Memorized
(m)
1 15
2 30
3 45
4 60

Using w = number of weeks and m = number of multiplication facts, which of the following equations is represented by the table Mr. Hudkins created?
Mathematics
1 answer:
Y_Kistochka [10]4 years ago
5 0

Answer:

m=15w

Step-by-step explanation:

i did the test before :)

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qaws [65]
2384598 + 6000000 = 8384598
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3 years ago
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Given the function defined in the table below, find the average rate of change, in simplest form, of the function over the inter
Inessa [10]

The average rate of change, in simplest form, of the function over the interval 2 ≤ x ≤ 10 is 9

<h3>How to find the average rate of change, in simplest form, of the function over the interval 2≤x≤10?</h3>

The interval is given as:

2 ≤ x ≤ 10

From the table of values, we have

f(2) = 34

f(10) = 106

The average rate of change, in simplest form, of the function over the interval 2≤x≤10 is calculated as;

Rate = (f(10) - f(2))/(10 - 2)

This gives

Rate =(106 - 34)/(10 - 2)

Evaluate

Rate = 9

Hence, the average rate of change, in simplest form, of the function over the interval 2 ≤ x ≤ 10 is 9

Read more about average rate of change at

brainly.com/question/8728504

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7 0
1 year ago
The price of a toy usually costing £50 is increased to £65 <br> Workout the percentage increase.
KATRIN_1 [288]

Answer:

30 percent increase

Step-by-step explanation:

3 0
3 years ago
David y Angie tienen dos cartulinas iguales. David corta la suya en 3 trozos iguales y Angie la corta en 7 trozos. Los dos usan
Bess [88]

Answer:

(i) David ha empleado \frac{2}{3} de la cartulina.

(ii) Angie ha empleado \frac{2}{7} de la cartulina.

(iii) David ha usado más cartulina.

Step-by-step explanation:

El problema indica que David y Angie emplean una cartulina del mismo tamaño cada uno. David corta la suya en 3 pedazos iguales, mientras que Angie obtiene 7 pedazos iguales. Finalmente, cada uno emplea dos de sus pedazos. A continuación, respondemos a las preguntas del enunciado:

(i) <em>¿Qué fracción de cartulina ha usado David?</em>

La fracción de cartulina empleada por David es igual a los pedazos utilizados divididos por el total de pedazos. Esto es:

x = \frac{2}{3}

David ha empleado \frac{2}{3} de la cartulina.

(ii) <em>¿Qué fracción de cartulina ha usado Angie?</em>

Aplicando el mismo procedimiento del punto anterior, tenemos que:

x = \frac{2}{7}

Angie ha empleado \frac{2}{7} de la cartulina.

(iii) <em>¿Quién ha usado más cartulina?</em>

La persona que ha usado la mayor cantidad de cartulina es aquella que tiene el menor denominador. Por tanto, David ha usado más cartulina.

7 0
3 years ago
LMNP is a rectangle. Find the value of x and the length of each diagonal. LN =7x+9 and MP=9x-9
PilotLPTM [1.2K]

Answer:

see explanation

Step-by-step explanation:

The diagonals of a rectangle are congruent, thus

MP = LN , substitute values

9x - 9 = 7x + 9 ( subtract 7x from both sides )

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LN = 7x + 9 = (7 × 9) + 9 = 63 + 9 = 72

MP = 9x - 9 = (9 × 9) - 9 = 81 - 9 = 72

7 0
4 years ago
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