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riadik2000 [5.3K]
3 years ago
11

Daniel decides to use the method of proportions and similar

Mathematics
2 answers:
Arte-miy333 [17]3 years ago
8 0

Answer:

The answer is B

Step-by-step explanation:

abruzzese [7]3 years ago
6 0

Answer:

It's C.

Step-by-step explanation:

Have a good day.

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Need help with 6,7,8
Burka [1]

Answer:


Step-by-step explanation:well I can't really understand the question but 6,7,8 are number rigt next to each others are intergers


7 0
3 years ago
Please help on a timed quiz
kenny6666 [7]

Answer: The range of the tree heights at yard work is greater than the range of the tree heights at the grow station

Step-by-step explanation:

yard works: 7,9,7,12,15

The grow station:9,11,6,12,7

mean of yard works = 7+9+7+12+15/5

=50/5=10

mean of grow station=

9+11+6+12+7 /5

=45/5 =9

The mean of tree heights at yard work is greater than that of grow station.

median(tree at yard work):7,7,9,12,15

median=9

median(tree at grow station)=6,7,9,11,12

median=9

The median of the tree height at yard work is equal to the median of that of tree station.

Range(yard work) = 15 - 7 =8

Range (tree station) =12-6=6

The range of the tree heights at yard work is greater to the tree heights at that of tree station

8 0
3 years ago
Read 2 more answers
Find the greatest common factor of the following monomials 49a4b3 21a4b5
Mazyrski [523]

Answer:

7a^4b^3

Step-by-step explanation:

49a^4b^3   \\    21a^4b^5

GCF: 7a^4b^3

3 0
3 years ago
I will give branliest to whoever answers this correctly.
Korvikt [17]

Answer: i think it is 357

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
In 2002, Tim was twice as old as Sue. In 1997 the sum of their ages was 32. In what year will Sue's age be three-fourths Tim's a
xxMikexx [17]

Answer:

Year 2030.

Step-by-step explanation

In 1997, Let Tim's age = <em>X</em> years

In 1997, Let Sue's age = <em>Y</em> years

After 5 years in 2002, Tim's age = (<em>X+ 5) </em>years

After 5 years in 2002, Sue's age = <em>(Y + 5)</em> years

Now, According to question,

<em>X </em>+ <em>Y</em> = 32    (sum of their ages) .......(1)

<em>Y </em>= 32 -<em> X</em>

(X + 5) = 2 (Y + 5) .......(2)

Substituting the value of <em>Y</em> in (2)

<em>X </em>+ 5 = 2 (32 - <em>X </em>+ 5)

<em>X </em>+ 5 = 2 (37 - <em>X </em>)

<em>X </em>+ 5 = 74 - 2<em>X </em>

3<em>X </em>=<em> </em>69

<em>X </em>= 69/3 = 23

Now ∵<em> Y</em> = 32 - <em>X  </em>and<em> X = </em>23

∴ <em>Y</em> = 32 - 23 = 9

So, In 1997, Tim's age = 23 years and Sue's age = 9 years.

Let the year in which Sue's age will be three-fourth times of Tim's age be t.

Sue's age after<em> t </em>years = (9 +<em> t) </em>years.

Tim's age after<em> t</em> years = (23 + <em>t</em>) years

According to question,

(9 + t) = \frac{3}{4} \times(23 + t)

4 (9 + t) = 3 (23 + t)

36 + 4t = 69 + 3t

<em>4t - 3t = 69 - 36</em>

<em>t = 33</em>

The Year in which Sue's age will be three-fourth times of Tim's age is:

= (1997 + 33) = 2030.

4 0
4 years ago
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