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telo118 [61]
3 years ago
8

How do you grow rice

SAT
2 answers:
stich3 [128]3 years ago
8 0

Explanation:

Ideally, you need at least 40 continuous days of warm temps over 70 F. (21 C.) to grow rice.

First, you need to find one or several plastic containers without holes. One or several depends upon how many miniature pseudo rice paddies you want to create. Next, either purchase rice seed from a gardening supplier or buy long grain brown rice from a bulk foods store or in a bag. Organically grown rice is best and it can’t be white rice, which has been processed.

Fill the bucket or plastic container with 6 inches (15 cm.) of dirt or potting soil. Add water up to 2 inches (5 cm.) over the soil level. Add a handful of the long grain rice to the bucket. The rice will sink to the dirt. Keep the bucket in a warm, sunny area and move it to a warm place at night.

Rice plants don’t need too much care from here on out. Keep the water level at 2 inches (5 cm.) or so above the dirt. When the rice plants are 5-6 inches (12.5-15 cm.) tall, increase the water depth to 4 inches (10 cm.). Then, allow the water level to lower on its own over a period of time. Ideally, by the time you harvest them, the plants should no longer be in standing water.

If all goes well, rice is ready to harvest in its fourth month. The stalks will go from green to gold to indicate it is time to harvest. Harvesting rice means cutting and gathering the panicles attached to the stalks. To harvest the rice, cut the stalks and allow them to dry, wrapped in a newspaper, for two to three weeks in a warm, dry place.

Once the rice stalks have dried, roast in a very low heat oven (under 200 F./93 C.) for around an hour, then remove the hulls by hand. That’s it; you can now cook with your very own home grown, long grain brown rice.

irinina [24]3 years ago
6 0

Answer:

put some rice in a pot

Then mix it up with some sauce

pour in some dirt

and you'll get some sweet plant

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Hello oddworld7836!

\huge \boxed{\mathbb{QUESTION} \downarrow}

Factor the expression into an equivalent form 12y² - 75.

\large \boxed{\mathfrak{Answer \: with \: Explanation} \downarrow}

12 y ^ { 2 } - 75

By observing the expression, we can see that, 3 is the only common factor in both the terms of the expression. So, take the common factor 3 out.

12 y ^ { 2 } - 75 \\  = 3\left(4y^{2}-25\right)

Now, look at (4y² - 25). They don't have any common factors but they appear in the form of the algebraic identity ⇨ a² - b² = (a + b) (a - b). Here,

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So, the (4y² + 25) becomes...

(4 {y}^{2}  - 25) \\  = \left(2y-5\right)\left(2y+5\right)

Now, bring the 3 (common factor) & rewrite the complete expression.

12 y ^ { 2 } - 75 \\  =  \boxed{ \boxed{ \bf \: 3\left(2y-5\right)\left(2y+5\right) }}

We can't further simplify it. Also, remember that the simplified form of an expression is equivalent to the expression. So, 3 (2y - 5) (2y + 5) is equivalent to 12y² - 75.

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