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tiny-mole [99]
2 years ago
9

Effective treatments for disease is often target the underlying blank that causes the disease

Advanced Placement (AP)
1 answer:
Irina-Kira [14]2 years ago
8 0

Answer:

Effective treatments for disease is often target the underlying pathogen that causes the disease.

Explanation:

Diseases are caused by microorganisms called pathogens.  These pathogens or microorganisms include viruses, bacteria, fungi, and parasites.  Also described as diseasing-causing germs, these infectious or biological agents cause diseases or illnesses to their hosts by disrupting their normal physiology.  The most effective prevention is hygiene, especially hand-washing, while treatment includes the use of medicines and vaccines.

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Why is often hard to tell who is responsible for a bureaucratic decision?
Grace [21]

Answer:

The executive committee is often officially responsible for making a company's big decisions while another, unofficial group, led by the CEO, seems to hold the real decision-making power.

Explanation:

8 0
2 years ago
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lisov135 [29]

Answer:

yes.

Explanation:

Thanks for blank screen

3 0
3 years ago
You have 400 mg of a radioisotope with a half-life of 5 minutes. How much will be left after 30 minutes?
shepuryov [24]
If the half-life is 5 minutes, then 30 minutes is equivalent to 6 half-lives. So, after six successive half-lives, the 400 mg of the radioisotope would have a mass of 400(0.5)⁶ = 6.25 mg.

Thus, A would be the correct answer choice here.
3 0
2 years ago
Use midpoints to approxiamte the area under the curve y=f(x) 5 sin(xx)!+ 2.5 cos(4xx) on the interval [0,1] using 10 equal subdi
alisha [4.7K]

Subdividing [0, 1] into 10 equally spaced intervals of length \Delta x=\frac{1-0}{10}=\frac1{10} gives the partition

[0,1] = \left[0,\dfrac1{10}\right] \cup \left[\dfrac1{10},\dfrac2{10}\right] \cup \cdots \cup \left[\dfrac9{10},1\right]

The i-th subinterval has left and right endpoints, respectively, given by

\ell_i = \dfrac{i-1}{10} \text{ and } r_i = \dfrac i{10}

where i\in\{1,2,3,\ldots,10\}.

The midpoint of the i-th interval is the average of these,

m_i = \dfrac{\ell_i+r_i}2 = \dfrac{2i-1}{20} \in \left\{\dfrac1{20},\dfrac3{20},\dfrac5{20},\ldots,\dfrac{19}{20}\right\}

We approximate the area under f(x) over [0, 1] by the Riemann sum,

\displaystyle \int_0^1 f(x) \, dx \approx \sum_{i=1}^{10} f(m_i) \Delta x \\\\ ~~~~~~~~ = \frac1{10} \sum_{i=1}^{10} \bigg(5\sin(\pi m_i) + 2.5 \cos(4\pi m_i)\bigg) \\\\ ~~~~~~~~ = \frac{\sin\left(\frac\pi{20}\right) + \sin\left(\frac{3\pi}{20}\right) + \cdots + \sin\left(\frac{19\pi}{20}\right)}2 \\\\ ~~~~~~~~~~~~ + \dfrac{\cos\left(\frac\pi5\right) + \cos\left(\frac{3\pi}5\right) + \cdots + \cos\left(\frac{19\pi}5\right)}4 \\\\ ~~~~~~~~ \approx 3.19623

(D)

6 0
2 years ago
How do scientists use the Doppler effect to measure the actual motion of stars?
ddd [48]
If the light waves are coming more frequently, then we know the star is moving toward earth. if the light waves are coming more slowly, we know the star is moving away. this is because the star gives the illusion that the light waves are coming at a slower pace when in fact, the frequency is the same the whole time
3 0
3 years ago
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