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2 years ago

PLSS HELPPP ME IM BEGGING ITS FOR A TEST DUE IN 5 MINS!!!!!!!!!!!!!!!!!!

Mathematics

2 answers:

Snezhnost [94]2 years ago

8 0

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Mumz [18]2 years ago

7 0

Answer:

Step-by-step explanation:

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Fernanda's expenditures for this month are: rent, $750.00; groceries, $346.00;

Ivahew [28]

The answer is 1719.09 because that’s the total

7 0

3 years ago

Read 2 more answers

There are 6 red marbles 4 blue marbles to yellow marbles. Sabrina picks 2 marbles without putting the first one back what is the

Yanka [14]

Answer:

P = 3/11

Step-by-step explanation:

There are:

6 red marbles

4 blue marbles

2 yellow marbles.

So there are a total of 12 marbles in the bag, such that each one has the same probability of being randomly picked.

We want to find the probability that the first pick is not yellow (so it can be either blue or red), and the second pick is a blue marble.

Now there are two cases.

The first marble is red and the second blue

the first marble is blue and the second blue

We need to find the probability in each case.

The probability that the first marble is red is equal to the quotient between the number of red marbles (6) and the total number of marbles (12)

p = 6/12

Now, for the second draw, we need a blue marble, the probability in this case is the quotient between the number of blue marbles (4) and the total number of marbles in the bag (now there are 11, because one is already taken)

q = 4/11

The joint probability is equal to the product of the individual probabilities, then:

P₁ = p*q = (6/12)*(4/11) = 2/11

And for the other case, we draw two blue marbles:

For the first draw, the probability is:

p = 4/12

And for the second draw, now there are 3 blue marbles and 11 total marbles, then the probability is:

q = 3/11

The joint probability is:

P₂ = (4/12)*(3/11) = 1/11

The total probability is then:

P = P₁ + P₂ = 2/11 + 1/11 = 3/11

4 0

3 years ago

What is the sum of the difference?

Alona [7]

Answer:

A. 9x^4 and 3x^5y

Step-by-step explanation:

there are two ways to solve this:

first way:

You can solve this my substituting numbers for x and y in this case i used 2 for x and 3 for y and see which one is equal to the original equations

the second way is the regular way

when you add or subtract numbers with variables and exponents you want to add the constants and add the exponents in this case $5x^{4} +4x^2$ is the same as $(5x+4x)^(4+4)$ = $9x^4$ and you can do the same process for subtraction