To get the number of members between 15 years and 30 years we proceed as follows:
z=(x-μ)/σ
where:
mean,μ=23
standard deviation, σ=4 years
thus
P(15<x<31)
when x=15
P(x<15)
z=(15-23)/4
z=-2
thus
P(x<15)=P(z<-2)=0.0228
when x=31
z=(31-23)/4
z=2
thus
P(x<31)=P(z<2)=0.9772
Hence:
P(15<x<31)=0.9544
hence the number of members between that age was:
0.9544×300
=286.32 people
~285 People
Answer: 285 people
Answer:
<u>∗ = 0.4x³</u>
Step-by-step explanation:
(15y + ∗)² = 225y²+12x³y+0.16x⁶
<u>Note:</u>
225y² = 15y * 15y = (15y)²
12x³y = 2 * 15y * 0.4x³
0.16x⁶ = 0.4x³ * 0.4x³ = (0.4x³)²
So, by factoring the right hand side:
225y²+12x³y+0.16x⁶ = (15y + 0.4x³)²
By comparing the left hand side with (15y + 0.4x³)²
<u>So, ∗ should be replaced with the monomial 0.4x³</u>
D would be the answer.Since you are adding the sum first hence the parentheses.
(30 0Z less then) is your answer :)
Ok so u have to multiply for this one
Work *Jake*:
So he spends 2 hours on each assignment. He has 3 assignments so u have to do :
2*3=6
He spend 6 hours a day doing home work so now u have to multiply that by 30:
6*30=180
Work *Orlando*:
So he spends 2 hours on each homework. He has 2 sheets each do so u have to multiply 2 and 2:
2*2=4
He spends 4 hours a day doing homwork so u have to multiply it by 30:
4*30=120
Answer:
So Jake spends 130 hours
Orlando spends 120 hours
Add both together:
120+130=250
They spend 250 hours together on work in 30 days/
