Answer:
A because science is not to be a math subject
Answer: D) thoughtful awareness
Explanation:
The thoughtful awareness can be a concern of the author. It is the attitude which is making author doubtful for making an use of social networking for interactions with friends and family. The author is aware about the leakage of information, risk on privacy and cyber conspiracy related to the use of social networking sites.
A method which would quickly reveal if the solution was saturated or unsaturated is to add heat to the solution and stir.
<h3>What is solubility?</h3>
Solubility can be defined as a terminology that describes how readily a chemical substance (compound) can be dissolved in a solvent to form a solution, which may either be saturated or unsaturated.
In Chemistry, a chemical substance (compound) is considered to be soluble if it dissolves completely in a solvent such as water.
In this experiment, a method which can be used by the student to quickly reveal if the solution was saturated or unsaturated is to add heat to the solution and stir because it will increase the rate in which it dissolves and settles at the bottom.
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Answer:
because they would tell other people that they know, and it would start out your business on a good foot as reliable and friendly. that alone would have people coming in to try it out for themselves. another reason would be because you don't want to look like a snotty business when you are just starting out and are small and not even anywhere near the big businesses.
The point slope form of the asymptote of the hyperbola is; y - 4 = ±(6/7)(x - 6)
- We are given the equation of the hyperbola as;
[(y + 4)²/36] - [(x - 6)²/49] = 1
- We can rewrite this equation as;
[(y + 1)²/6²] - [(x - 6)²/7²] = 1
- The general equation form of hyperbola is;
[(y - k)²/a²] - [(x - h)²/b²] = 1
- Comparing this general form to our given equation we can see that;
k = -4
h = 6
a = 6
b = 7
- Now the equation of the asymptote of a hyperbola follows the general formula;
y = ±[a(x - h)/b] + k
- Plugging in the relevant values gives us;
y = ±(6/7)(x - 6) - 4
>> y - 4 = ±(6/7)(x - 6)
Read more about hyperbola asymptotes at; brainly.com/question/12919612
