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Nonamiya [84]
3 years ago
10

which table represents viable solutions for y=5x, where x is the number of tickets sold for the school play a y is the amount of

money collected for the tickets?

Mathematics
1 answer:
STALIN [3.7K]3 years ago
8 0

Given:

The given equation is:

y=5x

Where x is the number of tickets sold for the school play a y is the amount of money collected for the tickets.

To find:

The correct table of values from the given options.

Solution:

We know that the number of tickets and amount of money collected for the tickets cannot be negative. So, options A and B are incorrect.

We have,

y=5x

For x=0,

y=5(0)

y=0

For x=10,

y=5(10)

y=50

For x=51,

y=5(51)

y=255

For x=400,

y=5(400)

y=2000

In option C, all the ordered pairs (0,0), (10,50), (51,255), (400,2000) are in the table. So, option C is correct.

For x=65

y=5(65)

y=325

Since the ordered pair (65,350) does not satisfy the given equation, therefore the option D is incorrect.

Hence, the correct option is C.

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7 0
3 years ago
The measurement of the edge of a cube is measured to be 12 inches, with a possible error of 0.03 inch. Use differentials to appr
adoni [48]

Answer:

A) possible error = 12.992

Possible values for the volume [1715,007,1740.992]

B) possible error = 4.325

Possible values for the surface area [859,675,868,325]

Step-by-step explanation:

The volumen of a cube is the cube of the length of a side. Thus, the meassurement of the volume is 12³ = 1728 inches³. To calculate the error, lets call Y the real value of the length,

Y = X + e, where e is the error and X = 12.

Y³ = (X+e)³ = X³ + 3X²e + 3Xe² + e³

the error is 0.03 inches, so we have that

Y³ = X³ + 12.96+0.0324+ 0.000027 = X³+12.992427 = X³+12.992 (rounded to 3 decimal places).

Thus, the absolute possible error is Y³- X³ = 12.992, and the volume of the cube is contained in the interval [X³-12.992,X³+12.992] = [1715,007,1740.992]

B) The surface area is 6 X². With X meassured as 12, the surface area is meassured by 6*12² = 864.

To calculate the absolute error, we take Y = X+e, with X and e as before. We have

6 Y² = 6*(X+e)² = 6X²+12Xe+6e² = 6X²+4.32+0.0054 = 6X²+4.3254

Hence, the absolute error is bounded by 6Y²-6X² = 4.3254 rounded by 4.325, and the value of the surface area is contained in the interval [6X² -4.325, 6X²+4.325] = [859,675, 868,325]

3 0
3 years ago
14.8 = n minus 0.3<br> n = negative 15.1<br> n = negative 14.5<br> n = 14.5<br> n = 15.1
dlinn [17]

Hello!

14.8 = n - 0.3

n - 0.3 = 14.8

n = 14.8 + 0.3

n = 15.1 → value of n

Good luck! :)

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3 years ago
What is 161 divisible by
kompoz [17]
<span>1, 7, 23, 161 is what can go into 161</span>
3 0
3 years ago
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Can someone help me with this??
kobusy [5.1K]
-4 by -5 here you are
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