Answer:
The second one:
L∪J={i,j,k,l,m,n,o}
Step-by-step explanation:
The union is the elements listed in either set.
So since l,m,n, and o are elements of set L, they will also be elements of whatever it is "unioned" with.
Since i,j,k,l and m are elements of set J, they will also be elements of whatever it is "unioned" with.
When you write the union, just be sure to include each element that occurs in either set once.
So the union of L and J is {i,j,k,l,m,n,o}.
The answer is the second one.
The intersection would actually be that upside down U thing, the ∩ symbol. The intersection of two sets is a list of elements that both sets include. So here the intersection would just consist of the elements l amd m.
Answer:
C. Mean
Step-by-step explanation:
We have been given that obtaining a measure of intelligence from a group of college students would likely yield a somewhat normal distribution (that is, there shouldn't be any extreme outliers).
We know that median is best measure of central tendency with extreme outliers, while mean is the best measure of central tendency when the data is normally distributed.
Mode is used when data are measured in a nominal scale.
Since the measure of intelligence from a group of college students yield a somewhat normal distribution, therefore, mean will be the best measure of central tendency.
Answer:
Use pythagorean theorem.
Step-by-step explanation:
The length of the shorter sides are 1 & 4
1^2+4^2=c^2
1+16=c^2
17=c^2
So, the length, rounded to the nearest whole inch, would be 4.
To find the perimeter, you need to find the side lengths first.
The short sides are 6 & 7.
6^2+7^2=c^2
36+49=c^2
85=c^2
So the length for that would be 8, in the nearest whole number.
Add all of the side lengths together.
6+7+8= 21
The perimeter is 21.
Answer:
9.37 divide by two = 4.685
4.685 in 2DP = 4.68
Step-by-step explanation:
i hoped this helps.
Answer:
B
Step-by-step explanation:
The chances of the first student walking to school is 7/30.
Without replacement, there are 29 students left. Hence the chance of the second student walking to school is 6/29 of the original 7/30 chance.
