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Complete Question
A boat sails 4km on a bearing of 038 degree and then 5km on a bearing of 067 degree.(a)how far is the boat from its starting point.(b) calculate the bearing of the boat from its starting point
Answer:
a)8.717km
b) 54.146°
Step-by-step explanation:
(a)how far is the boat from its starting point.
We solve this question using resultant vectors
= (Rcos θ, Rsinθ + Rcos θ, Rsinθ)
Where
Rcos θ = x
Rsinθ = y
= (4cos38,4sin38) + (5cos67,5sin67)
= (3.152, 2.4626) + (1.9536, 4.6025)
= (5.1056, 7.065)
x = 5.1056
y = 7.065
Distance = √x² + y²
= √(5.1056²+ 7.065²)
= √75.98137636
= √8.7167296826
Approximately = 8.717 km
Therefore, the boat is 8.717km its starting point.
(b)calculate the bearing of the boat from its starting point.
The bearing of the boat is calculated using
tan θ = y/x
tan θ = 7.065/5.1056
θ = arc tan (7.065/5.1056)
= 54.145828196°
θ ≈ 54.146°
The answer you are looking for is 3sq^2.
This is because.
2.5*2=5, and 13.25-5=8.25, and 8.25/2.75=3
Step-by-step explanation:
Answer:
565776
Step-by-step explanation:
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Answer:
b) 7×8
c) 4×14
d) 2×28
Step-by-step explanation:
A factor pair of a number is a pair of numbers that, when multiplied will result in the given number.
The factors of 56 are: 1, 2, 4, 7, 8, 14, 28, and 56.
The factor pairs are:
Out of the options, only Option A is not a factor pair.
