Use a quadratic equation to find two real numbers with a sum of 43 and a product of 306

Please help with this ASAP

uranmaximum [27]

Answer:

7w^3/5v

Step-by-step explanation:

42v^3w^4/30v^4w

42 = 6 * 7

30 = 6*5 , factor

6*7v^3w^4/6*5v^4w

6 is common, cancel

7v^3w^4/5v^4w

simplify w^4/w = w^3

v^3/v^4 = 1/v

therefore, 7w^3/5v is the answer

7 0

2 years ago

PLS HELPPPP ITS PROB EASY BUT I HAVE SO MANY LATE WORK TO DO:)))

kumpel [21]

Answer:

It’s C

Step-by-step explanation:

4 0

3 years ago

Given: ∆PQR, m∠R = 90° m∠PQR = 75° M ∈ PR , MP = 18 m∠MQR = 60° Find: RQ

tensa zangetsu [6.8K]

Answer: RQ= 8.99 ( approx)

Step-by-step explanation:

Let MR= x

Since, In triangle, PRQ, tan 75°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{18+x}{tan 75^{\circ}}$

Now, In triangle MRQ,

tan 60°= $\frac{18+x}{RQ}$

⇒ RQ= $\frac{x}{tan 60^{\circ}}$

On equating both values of RQ,

$\frac{18+x}{tan 75^{\circ}}=\frac{x}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=\frac{tan 75^{\circ}}{tan 60^{\circ}}$

⇒ $\frac{18+x}{x}=2.15470053838$

⇒ $18=2.15470053838x-x$

⇒ $x=15.5884572681$ ≈15.60

Thus RQ=8.99999999999≈8.99

6 0

3 years ago

can you please just help me so that i dont fail this one because everything i've been doing i've been failing and it's because i

Julli [10]

1. r=5
2. x=2
3. x=-3
4. y=11
5. x=-11

6 0

3 years ago

Read 2 more answers

At a school fair, students were challenged to hit one of the small congruent circles on the large rectangular board with a ball.

shtirl [24]

Answer:

~4.7%

Step-by-step explanation:

Area of the rectangle: 35*52=1820

Area of 1 small circle: A=πr2=π·32≈28.27433

28.27433*3=84.82299

84.82299/1820=0.04660603846

Therefore, about 4.7%

6 0

2 years ago