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pickupchik [31]
3 years ago
10

Solve the equation: -7/10 = 3a/4 - 13/20? Help pleaseeee! Thanks

Mathematics
1 answer:
poizon [28]3 years ago
4 0

Answer:

Solving the equation -\frac{7}{10}=\frac{3a}{4}-\frac{13}{20} we get: \mathbf{a=-\frac{1}{15} }

Step-by-step explanation:

We need to solve the equation:

-\frac{7}{10}=\frac{3a}{4}-\frac{13}{20}

And find the value of a

Solving the equation: -\frac{7}{10}=\frac{3a}{4}-\frac{13}{20}

First we will be Switching sides

\frac{3a}{4}-\frac{13}{20}=-\frac{7}{10}

Now, for finding value of a we will be adding 13/20 on both sides

\frac{3a}{4}-\frac{13}{20}+\frac{13}{20}=-\frac{7}{10}+\frac{13}{20}

\frac{3a}{4}=-\frac{7}{10}+\frac{13}{20}

Now, on right hand side, Taking LCM of denominators i.e 10 and 20, we get 20 and simplifying:

\frac{3a}{4}=\frac{-7*2+13}{20}\\\frac{3a}{4}=\frac{-14+13}{20}\\\frac{3a}{4}=\frac{-1}{20}

Now, multiply both sides by 4/3

\frac{3a}{4}\times \frac{4}{3} =\frac{-1}{20}\times \frac{4}{3}\\a=\frac{-1}{5}\times \frac{1}{3}\\a= \frac{-1}{15}

So, solving the equation -\frac{7}{10}=\frac{3a}{4}-\frac{13}{20} we get: \mathbf{a=-\frac{1}{15} }

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7 0
3 years ago
To estimate the mean height μ of male students on your campus,you will measure an SRS of students. You know from government data
nexus9112 [7]

Answer:

a) \sigma = 0.167

b) We need a sample of at least 282 young men.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

This Zscore is how many standard deviations the value of the measure X is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

(a) What standard deviation must x have so that 99.7% of allsamples give an x within one-half inch of μ?

To solve this problem, we use the 68-95-99.7 rule. This rule states that:

68% of the measures are within 1 standard deviation of the mean.

95% of the measures are within 2 standard deviations of the mean.

99.7% of the measures are within 3 standard deviations of the mean.

In this problem, we want 99.7% of all samples give X within one-half inch of \mu. So X - \mu = 0.5 must have Z = 3 and X - \mu = -0.5 must have Z = -3.

So

Z = \frac{X - \mu}{\sigma}

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(b) How large an SRS do you need to reduce the standard deviationof x to the value you found in part (a)?

You know from government data that heights of young men are approximately Normal with standard deviation about 2.8 inches. This means that \sigma = 2.8

The standard deviation of a sample of n young man is given by the following formula

s = \frac{\sigma}{\sqrt{n}}

We want to have s = 0.167

0.167 = \frac{2.8}{\sqrt{n}}

0.167\sqrt{n} = 2.8

\sqrt{n} = \frac{2.8}{0.167}

\sqrt{n} = 16.77

\sqrt{n}^{2} = 16.77^{2}

n = 281.23

We need a sample of at least 282 young men.

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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