Answer:
Segment EG ≅ segment EG by the reflexive property.
Step-by-step explanation:
In the diagram given, already, two angles (<H and <HEG) of ∆HEG has been stated to be equal to two corresponding angles (<F and <FGE) of ∆FGE.
To prove that ∆HEG is congruent to ∆HEG by the Angle-Angle-Side Congruence Theorem, we need to state that they also have one corresponding side that is congruent.
Therefore, the statement and reason that will complete the proof would be:
Segment EG is congruent to segment EG by the reflexive property.
Both triangles share the same segment, EG. This completes the proof.
