Answer:
Slope is -3
y-intercept is -3 and equation is y=-3x-3
The maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
<h3>What is the range?</h3>
The range is the difference between the maximum and minimum.
Given to us
The standard diameter of a golf ball is 42.67 mm.
The discrepancy in diameter is more than 0.002 mm.
As it is given to us that the standard diameter of the golf ball is 42.67 mm while the discrepancy in diameter is more than 0.002 mm.
Maximum acceptable diameter = 42.67 mm + 0.002 mm = 42.672 mm
Minimum acceptable diameter = 42.67 mm - 0.002 mm = 42.668 mm
Hence, the maximum and minimum acceptable diameter of the golf ball in the factory will be 42.672 mm to 42.668 mm.
Learn more about Range:
brainly.com/question/3507706
Answer:
60 tiles left over
Step-by-step explanation:
the lobby needs 30 x 8 = 240 tiles.
she has 6 x 50 = 300 tiles
300 - 240 = 60 left over
The answer is 0.0017. Do you not have a calculator?
Answer:
a.) f(x) = 
where 90 < x < 120
b.) 
c.)
d.) 
Step-by-step explanation:
Let
X be a uniform random variable that denotes the actual charging time of battery.
Given that, the actual recharging time required is uniformly distributed between 90 and 120 minutes.
⇒X ≈ ∪ ( 90, 120 )
a.)
Probability density function , f (x) = 
where 90 < x < 120
b.)
P(x < 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{90} = \frac{1}{30} [ 110 - 90 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B90%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2090%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
c.)
P(x > 100 ) = 
= ![\frac{1}{30}[x]\limits^{120}_{100} = \frac{1}{30} [ 120 - 100 ] = \frac{1}{30} [ 20] = \frac{2}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B120%7D_%7B100%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20120%20-%20100%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2020%5D%20%3D%20%5Cfrac%7B2%7D%7B3%7D)
d.)
P(95 < x< 110) = 
= ![\frac{1}{30}[x]\limits^{110}_{95} = \frac{1}{30} [ 110 - 95 ] = \frac{1}{30} [ 15] = \frac{1}{2}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B30%7D%5Bx%5D%5Climits%5E%7B110%7D_%7B95%7D%20%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%20110%20-%2095%20%5D%20%3D%20%5Cfrac%7B1%7D%7B30%7D%20%5B%2015%5D%20%3D%20%5Cfrac%7B1%7D%7B2%7D)
