-2 = - x + x^2 -4 => x^2 - x - 4 + 2 = 0
x^2 - x - 2 = 0
a is the coefficient of x^2 => a = 1
b is the coefficient of x => b = - 1
c is the constant term => c = - 2
quadratic equation: [- b +/- √(b^2 - 4ac) ] / 2a =
= { 1 +/- √[ (-1)^2 - 4(1)(-2)] } / (2(1) = { 1 +/- √ (1 + 8) } / 2 = {1 +/- √9} / 2 =
= { 1 +/- 3} / 2
2x -4y= 28
⇒ -4y= 28 -2x
⇒ y= (28 -2x)/ (-4)
⇒ y= 28/(-4) -(2x)/ (-4)
⇒ y= -7 + 1/2x
The final answer is y= -7 + 1/2x~
Answer:
B. 
Step-by-step explanation:
The hypotenuse leg theorem (HL) requires the proof that the hypotenuse and the corresponding leg of the triangles to be equal in length. From the diagram, it can be found that 
is a common (shared) side of both triangles, so the additional fact needed is for the hypotenuses to be the same length.
∴ is the additional fact needed to prove 
Hope this helps :)
