recall from the previous posting, 2⁸ = 256, so that's one way to represent it.
now, another way hmmm
The given problem is very confusing since it was copy
pasted directly from the source so the equations look scrambled and plus it was
one words. After my own translation, I believe the given numbers are:
4 ⋅ 10^6
and
1 ⋅ 10^4
The symbol ⋅ means
that the two numbers are multiplied while the symbol ^ means an exponent of.
Now we are asked to find how much the 1st number is larger than the
2nd number. To solve this, we simply have to divide the bigger
number by the smaller number. Since 4 ⋅ 10^6
has bigger exponent than 1 ⋅ 10^4
then it is the bigger number.
Ratio = 4 ⋅ 10^6 /
1 ⋅ 10^4
Ratio = 4 ⋅ 10^2 =
400
Therefore 4 ⋅ 10^6
is 400 times bigger than 1 ⋅ 10^4.
Answer:
<span>400 times</span>
The three numbers are 12, 18 and 24
Arithmetic progression
Let the 3 number in arithmetic progression be:
a-d, d, a+d ...
If their sum is 3, then;
a-d+d+a+d = 3
2a + d = 3 ........... 1
If the sum of their squares is 11, then;
(a-d)² + d² + (a+d)² = 11
a²-2ad+d²+d²+a²+2ad+d² 11
2a²+3d² = 11 ....... 2
Solving the equations simultaneously, d = 6 and a = 12
First-term = 12
second term = 18
Thirs term = 24
Hence the three numbers are 12, 18 and 24
Hope this helps you!!!!!! :D
Answer:
The second one, -11/12
Step-by-step explanation:
I used a website so sorry I don't have an explanation
Answer:
JN = 32
Step-by-step explanation:
Δ JMN and Δ JKL are similar ( AA postulate )
then the ratios of corresponding sides are in proportion, that is
= 
( substitute values )
= 
= ( cross- multiply )
11 JN = 8(JN + 12)
11 JN = 8 JN + 96 ( subtract 8 JN from both sides )
3 JN = 96 ( divide both sides by 3 )
JN = 32
