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Olenka [21]
3 years ago
12

A pet store has 6 cats. Here are their weights (in pounds).

Mathematics
2 answers:
slega [8]3 years ago
6 0
2. 7-9=2 those are the middle two numbers so you subtract them to get 2
Veronika [31]3 years ago
3 0
Your answer for this would be 2, hoped this helped!
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Please someone actually help :((( honestly im just gonna drop out
Lorico [155]

Answer:

12

Step-by-step explanation:

4u - 8u = -63 + 15 ( collecting like terms)

-4u = -48

u = 12

8 0
3 years ago
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What do the expressions (33) and (34) have in common?
lana66690 [7]
The two expressions are both rational numbers- they are ending, whole and have no decimals.
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3 years ago
Evaluate 3x2-1 when x=2
Nezavi [6.7K]
I would guess 61 in my school we only do things like this x4 - 5 x times four minus five so I don’t know if that’s right but that would be my guess if that isn’t right it would be 62 times 2
7 0
3 years ago
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What is 271,403 rounded to the nearest ten thousand
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8 0
3 years ago
Using Euler’s Method with a step size of h=0.5, estimate the value for y(3) for the differential equation xy dy/dx= 1+ln(x^2), w
lora16 [44]
Euler's method uses the recurrence relation

y_{n+1}=y_n+hf(x_n,y_n)

to approximate the value of the solution y(x) to the ODE y'=f(x,y).

xy\dfrac{\mathrm dy}{\mathrm dx}=1+\ln(x^2)\implies y'=\dfrac{1+\ln(x^2)}{xy}=f(x,y)

With a step size of h=0.5, there will only be two steps necessary to find the approximate value of y(3) based on the initial point y(2)=5. See the attached table below for the computation results.

To demonstrate how the table is generated: Since y(2)=5, you are using (x_0,y_0)=(2,5).

y_1=y_0+hf(x_0,y_0)
y_1=5+0.5\times\dfrac{1+\ln(2^2)}{2\times5}
y_1\approx5.1193

The next point then uses x_1=x_0+0.5=2.5

y_2=y_1+hf(x_1,y_1)
y_1=y_1+0.5\times\dfrac{1+\ln(2.5^2)}{2.5y_1}
y_2\approx5.230

8 0
3 years ago
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