Answer:
a) The probability that exactly eight arrive during the hour and all eight have no violations is 0.0005.
b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:

c) The probability that eight "no-violation" cars arrive during the next hour is 0.030.
Step-by-step explanation:
a) The probability that exactly eight arrive during the hour and all eight have no violations is equal to the product of the probability of arrival of 8 vehicules and the probability of having 8 vehicules with no violations.

b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:
![P(X=y\,\&\,nv=8)=P(nv=8|X=y)*P(X=y)\\\\P(X=y\,\&\,nv=8)=[\binom{y}{8}(0.5)^8*(0.5)^{y-8}]*\frac{8^ye^{-8}}{y!} =\frac{y!}{8!(y-8)!}0.5^y *8^y*\frac{e^{-8}}{y!}\\\\ P(X=y\,\&\,nv=8)=(\frac{y!}{y!})(0.5*8)^y\frac{e^{-8}}{8!(y-8)!}=\frac{4^ye^{-8}}{8!(y-8)!}](https://tex.z-dn.net/?f=P%28X%3Dy%5C%2C%5C%26%5C%2Cnv%3D8%29%3DP%28nv%3D8%7CX%3Dy%29%2AP%28X%3Dy%29%5C%5C%5C%5CP%28X%3Dy%5C%2C%5C%26%5C%2Cnv%3D8%29%3D%5B%5Cbinom%7By%7D%7B8%7D%280.5%29%5E8%2A%280.5%29%5E%7By-8%7D%5D%2A%5Cfrac%7B8%5Eye%5E%7B-8%7D%7D%7By%21%7D%20%3D%5Cfrac%7By%21%7D%7B8%21%28y-8%29%21%7D0.5%5Ey%20%2A8%5Ey%2A%5Cfrac%7Be%5E%7B-8%7D%7D%7By%21%7D%5C%5C%5C%5C%20P%28X%3Dy%5C%2C%5C%26%5C%2Cnv%3D8%29%3D%28%5Cfrac%7By%21%7D%7By%21%7D%29%280.5%2A8%29%5Ey%5Cfrac%7Be%5E%7B-8%7D%7D%7B8%21%28y-8%29%21%7D%3D%5Cfrac%7B4%5Eye%5E%7B-8%7D%7D%7B8%21%28y-8%29%21%7D)
c) Using the result of point (b) we can express the probability that eight "no violation" vehicules arrive durting the next hour as:

Answer:
Translation is moving an object to one place to another.
Step-by-step explanation:
Answer:
Step-by-step explanation:
Answer:
Since ZE and ZF are vertical angles, they are congruent.
8x+8 = 2x+38
8 = 2x-8x+38
8 = -6x+38
8-38 = -6x
-30 = -6x
x = -30/-6
x = 5
Answer:
1st qns: A
2nd qns: B
Step-by-step explanation:
The ans is A as its 1/6