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Delvig [45]
3 years ago
7

Suppose you start at the origin, move along the x-axis a distance of 4 units in the positive direction, and then move downward a

long the z-axis a distance of 2 units. What are the coordinates of your position
Mathematics
1 answer:
SVEN [57.7K]3 years ago
7 0

Answer:

B = (x+4,y-2)

Step-by-step explanation:

Let the current position be A:

A = (x,y)

Required

Determine the new position

First, you move 4 units to the right.

This is represented as x + a

Where a is the number of units to the right

In this case:

a = 4

So, we have: x + 4

Then you move 2 units downwards

This is represented as y - b

Where b is the number of units downwards.

In this case:

b = 2

So, we have: y - 2

So, the new position (B) is:

B = (x+4,y-2)

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Automobiles arrive at a vehicle equipment inspection station according to a Poisson process with rate α = 8 per hour. Suppose th
Elis [28]

Answer:

a) The probability that exactly eight arrive during the hour and all eight have no violations is 0.0005.

b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:

P(X=y\,\&\,nv=8)=\frac{4^ye^{-8}}{8!(y-8)!}

c) The probability that eight "no-violation" cars arrive during the next hour is 0.030.

Step-by-step explanation:

a) The probability that exactly eight arrive during the hour and all eight have no violations is equal to the product of the probability of arrival of 8 vehicules and the probability of having 8 vehicules with no violations.

P(X=8\,\&\,no\, violations)=P(no\, violations|X=8)*P(X=8)\\\\P(X=8\,\&\,nv)=(0.5)^8*\frac{8^8e^{-8}}{8!} = 0.0039*0.1396=0.0005

b) For any fixed y ≥ 8, the probability that y arrive during the hour, of which eight have no violations is:

P(X=y\,\&\,nv=8)=P(nv=8|X=y)*P(X=y)\\\\P(X=y\,\&\,nv=8)=[\binom{y}{8}(0.5)^8*(0.5)^{y-8}]*\frac{8^ye^{-8}}{y!} =\frac{y!}{8!(y-8)!}0.5^y *8^y*\frac{e^{-8}}{y!}\\\\ P(X=y\,\&\,nv=8)=(\frac{y!}{y!})(0.5*8)^y\frac{e^{-8}}{8!(y-8)!}=\frac{4^ye^{-8}}{8!(y-8)!}

c) Using the result of point (b) we can express the probability that eight "no violation" vehicules arrive durting the next hour as:

P(nv=8)=\sum\limits^\infty_{y=8} {\frac{4^ye^{-8}}{8!(y-8)!}}=\frac{e^{-8}}{8!} \sum\limits^\infty_{y=8} {\frac{4^y}{(y-8)!}}=\frac{e^{-8}4^{8}}{8!} \sum\limits^\infty_{y=8} {\frac{4^{y-8}}{(y-8)!}}\\\\P(nv=8)=\frac{e^{-8}4^{8}}{8!} \sum\limits^\infty_{z=0} {\frac{4^{z}}{z!}}=\frac{e^{-8}4^{8}}{8!}*e^4=\frac{e^{-4}4^{8}}{8!}\\\\P(nv=8)= 0.030

5 0
3 years ago
What does translation means in math? I am taking a quiz on this right now, I need an answer ASAP!!!!!!
Morgarella [4.7K]

Answer:

Translation is moving an object to one place to another.

Step-by-step explanation:


8 0
3 years ago
A truckload of cement weighs approximately 3
dexar [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
ZE and ZF are vertical angles with mZE = 8x + 8 and mZF = 2x +38.<br> What is the value of x?
Dovator [93]

Answer:

Since ZE and ZF are vertical angles, they are congruent.

8x+8 = 2x+38

8 = 2x-8x+38

8 = -6x+38

8-38 = -6x

-30 = -6x

x = -30/-6

x = 5

7 0
3 years ago
Read 2 more answers
could you answer both these questions? Will give brainilest!! To answer give eithr a,b,c or d. THANK U
fgiga [73]

Answer:

1st qns: A

2nd qns: B

Step-by-step explanation:

The ans is A as its 1/6

8 0
4 years ago
Read 2 more answers
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