3 years ago

I am trying to figure this question: 1 + tan^2A = Sec^2A

Mathematics

1 answer:

chubhunter [2.5K]3 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )

$\frac{cos^2A}{cos^2A}$ + $\frac{sin^2A}{cos^2A}$ = $\frac{1}{cos^2A}$ , that is

1 + tan²A = sec²A ← as required

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