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2 years ago

I am trying to figure this question: 1 + tan^2A = Sec^2A

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )

$\frac{cos^2A}{cos^2A}$ + $\frac{sin^2A}{cos^2A}$ = $\frac{1}{cos^2A}$ , that is

1 + tan²A = sec²A ← as required

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A person's blood pressure is monitored by taking 4 readings daily. The probability distribution of his reading had a mean of 13

ss7ja [257]

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b) Normal distribution

c) 0.0026

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 4

Mean = 133

Standard deviation = 5

a) Mean and the standard deviation of the sampling distribution of the sample mean for the four observations each day.

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The standard deviation of the sampling distribution is given by:

$\sigma_s = \dfrac{\sigma}{\sqrt{n}} = \dfrac{5}{\sqrt{4}} = 2.5$

b) Shape of the sampling distribution

Central limit theorem:

When a large sample is drawn from a normal distribution, then the distribution of sample means approaches a normal distribution.

Since the distribution is normal, the sampling distribution of the sample mean will be bell shaped and follow a normal distribution.

c) P(sample mean exceeds 140)

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2 years ago