2 years ago

I am trying to figure this question: 1 + tan^2A = Sec^2A

Mathematics

1 answer:

chubhunter [2.5K]2 years ago

3 0

Answer:

see explanation

Step-by-step explanation:

Using the Pythagorean identity

cos²A + sin²A = 1 ( divide terms by cos²A )

$\frac{cos^2A}{cos^2A}$ + $\frac{sin^2A}{cos^2A}$ = $\frac{1}{cos^2A}$ , that is

1 + tan²A = sec²A ← as required

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Read 2 more answers

In which step did Viet make an error? 2 ( x − 3 ) 2 + 4 = 102 2 ( x − 3 ) 2 = 106 Step 1 ( x − 3 ) 2 = 53 Step 2 x − 3 = ± 53 St

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Answer:

Step 2

Step-by-step explanation:

Given

Step 1: $2(x - 3)^2 + 4 = 102$

Step 2: $2(x - 3)^2 = 106$

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Required

Where did Viet made an error?

The step 1 indicates the original question.

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To get to step 2, we have to subtract 4 from both sides of the equation.

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However, the above expression is different from Viet's evaluation.

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2 years ago

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